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Veseljchak [2.6K]
3 years ago
8

The upper-left coordinates on a rectangle are (-6,0)(−6,0)left parenthesis, minus, 6, comma, 0, right parenthesis, and the upper

-right coordinates are (-4,0)(−4,0)left parenthesis, minus, 4, comma, 0, right parenthesis. The rectangle has an area of 121212 square units. Draw the rectangle on the coordinate plane below.
Mathematics
1 answer:
nikklg [1K]3 years ago
6 0

Answer:

See attachment for rectangle

Step-by-step explanation:

Given

A = (-6,0)

B = (-4,0)

Area = 12

Required

Draw the rectangle

First, we calculate the distance between A and B using distance formula;

AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}

So, we have:

AB = \sqrt{(-6 - -4)^2 + (0- 0)^2}

AB = \sqrt{(-2)^2 + (0)^2}

AB = \sqrt{4 + 0}

AB = \sqrt{4}

AB = 2

The above represents the length of the triangle.

Next, calculate the width using:

Length * Width = Area

2* Width = 12

Divide both sides by 2

Width = 6

This implies that, the width of the rectangle is 6 units.

We have:

A = (-6,0)

B = (-4,0)

Since A and B are at the upper left and right, then the ther two points are below.

6 units below each of the above point are:

C = (-6,0-6)\\ => C = (-6,-6)

D = (-4,0-6) => D = (-4,-6)

Hence, the points of the rectangle are:

A = (-6,0)

B = (-4,0)

C = (-6,-6)

D = (-4,-6)

<em>See attachment for rectangle</em>

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