Question

The upper-left coordinates on a rectangle are (-6,0)(−6,0)left parenthesis, minus, 6, comma, 0, right parenthesis, and the upper-right coordinates are (-4,0)(−4,0)left parenthesis, minus, 4, comma, 0, right parenthesis. The rectangle has an area of 121212 square units. Draw the rectangle on the coordinate plane below.

Answer 1

Answer:

See attachment for rectangle

Step-by-step explanation:

Given

$A = (-6,0)$

$B = (-4,0)$

$Area = 12$

Required

Draw the rectangle

First, we calculate the distance between A and B using distance formula;

$AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}$

So, we have:

$AB = \sqrt{(-6 - -4)^2 + (0- 0)^2}$

$AB = \sqrt{(-2)^2 + (0)^2}$

$AB = \sqrt{4 + 0}$

$AB = \sqrt{4}$

$AB = 2$

The above represents the length of the triangle.

Next, calculate the width using:

$Length * Width = Area$

$2* Width = 12$

Divide both sides by 2

$Width = 6$

This implies that, the width of the rectangle is 6 units.

We have:

$A = (-6,0)$

$B = (-4,0)$

Since A and B are at the upper left and right, then the ther two points are below.

6 units below each of the above point are:

$C = (-6,0-6)$ => $C = (-6,-6)$

$D = (-4,0-6)$ => $D = (-4,-6)$

Hence, the points of the rectangle are:

$A = (-6,0)$

$B = (-4,0)$

$C = (-6,-6)$

$D = (-4,-6)$

See attachment for rectangle