Complete question:
A college dormitory room measures 14 ft wide by 13 ft long by 6 ft high. Weight density of air is 0.07 lbs/ft3. What is the weight of air in it under normal conditions?
Answer:
the weight of the air is 76.44 lbs
Explanation:
Given;
dimension of the dormitory, = 14 ft by 13 ft by 6 ft
density of the air, = 0.07 lbs/ft³
The volume of the air in the dormitory room = 14 ft x 13 ft x 6 ft
= 1092 ft³
The weight of the air = density x volume
= 0.07 lbs/ft³ x 1092 ft³
= 76.44 lbs
Therefore, the weight of the air is 76.44 lbs
Gravity lets all objects fall to the ground at the same speed, 9.8 m/s/s. If the force of gravity were stronger, such as 10 m/s/s, the rate of acceleration would be faster.
<span>reflection, rotation, translation</span>
A and B, one wavelength is crest too crest
Answer:
C
Explanation:
Centripetal acceleration is:
a = v² / r
First, convert km/h to m/s:
108 km/h × (1000 m / km) × (1 h / 3600 s) = 30 m/s
Therefore, the acceleration is:
a = (30 m/s)² / 300 m
a = 3 m/s²