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VashaNatasha [74]
3 years ago
11

Two identical projectiles were projected at 200 km/h the first one is at an angle 60 to the horizontal while the second one is a

t angle of 60 to vertical which projectile reaches a greater horizonatal range
Physics
1 answer:
Setler79 [48]3 years ago
3 0

Answer:

The angle that will have the most range (Goes further) <u>will be the one that is shot with 60 ° with the horizontal. </u>

Since the one that shoots with respect to the vertical, it will only reach higher. And it won't go as far as the horizontal.

Greetings.

Danna.

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If two objects collid and one is initially at rest, is it possible for both to be at rest after the collision?
Ludmilka [50]

Answer:

<em>Is it NOT possible for both particles to be at rest after the collision</em>

Explanation:

<u>Law Of Conservation Of Linear Momentum</u>

The total linear momentum of a system of particles is conserved regardless of their internal interactions while no external force is applied to the system. If m_1 and m_2 are the masses of two particles, and only one of them is at rest, there is a non-zero total linear momentum, i.e.

P_1=m_1v_1+m_2v_2

if at least one of the speeds is not zero, the total initial linear momentum is not zero.

If after the collision, both particles remain at rest, both speeds will be zero and the total linear momentum won't be conserved.

So, is it NOT possible for both particles to be at rest after the collision

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3 years ago
If you have just combed your hair and you hold the comb near a small, uncharged object, what will most likely happen?
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A circuit contains a resistor in series with a capacitor, the series combination being connected across the terminals of a batte
Natali5045456 [20]

Answer:

18.4 s

Explanation:

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\tau = RC

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\tau = 4.6 s

R=1.4\cdot 10^4 \Omega

So we can find the capacitance

C=\frac{\tau}{R}=\frac{4.6 s}{1.4\cdot 10^4 \Omega}=3.29\cdot 10^{-4} F

Now in the second circuit, the new resistance is

R=5.6\cdot 10^4 \Omega

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Answer:

5.5 N at 50.8° north of west.

Explanation:

To find the resultant of these forces, we have to resolve each force along the x- and y-direction, then find the components of the resultant force, and then calculate the resultant force.

The three forces are:

F_1=3.0 N (east)

F_2=4.0 N (west)

F_3=5.0 N (at 60° north of west)

Taking east as positive x-direction and north as positive y-direction, the components of the forces along the 2 directions are:

F_{1x}=3.0 N\\F_{1y}=0

F_{2x}=-4.0 N\\F_{2y}=0

F_{3x}=-(5.0)(cos 60^{\circ})=-2.5 N\\F_{3y}=(5.0)(sin 60^{\circ})=4.3 N

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Therefore, the magnitude of the resultant force is

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And the direction is:

\theta=tan^{-1}(\frac{F_y}{|F_x|})=tan^{-1}(\frac{4.3}{3.5})=50.8^{\circ}

And since the x-component is negative, it means that this angle is measured as north of west.

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