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Novay_Z [31]
3 years ago
12

State Ohms law in easy words

Physics
2 answers:
Alexus [3.1K]3 years ago
7 0

Answer:

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

tino4ka555 [31]3 years ago
5 0

a law in electricity : the strength of a direct current is directly proportional to the potential difference and inversely proportion to the resistance of the circuit .

hope this helps you

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Calculate the propellant mass required to launch a 2000 kg spacecraft from a 180 km circular orbit on a Hohmann transfer traject
Finger [1]

Answer:

t = 12,105.96 sec

Explanation:

Given data:

weight of spacecraft is 2000 kg

circular orbit distance to saturn = 180 km

specific impulse = 300 sec

saturn orbit around the sun R_2 = 1.43 *10^9 km

earth orbit around the sun R_1= 149.6 * 10^ 6 km

time required for the mission is given as t

t = \frac{2\pi}{\sqrt{\mu_sun}} [\frac{1}{2}(R_1 + R_2)]^{3/2}

where

\mu_{sun} is gravitational parameter of sun =  1.32712 x 10^20 m^3 s^2.t = \frac{2\pi}{\sqrt{ 1.32712 x 10^{20}}} [\frac{1}{2}(149.6 * 10^ 6 +1.43 *10^9 )]^{3/2}

t = 12,105.96 sec

6 0
3 years ago
46. Nuclear generating plants use the potential
nydimaria [60]

Answer:

nuclear battery to generate energy

4 0
2 years ago
Find the current in the thin straight wire if the magnetic field strength is equal to 0.00005 T at distance 5 cm. ​
Elodia [21]

Answer:

Answer

Correct option is

A

5×10

−6

tesla

I=5A

x=0.2m

Magnetic field at a distance 0.2 m away from the wire.

B=

2πx

μ

0

I

=

2π×0.2

4π×10

−7

×5

=10×5×10

−7

=5×10

−6

tesla

3 0
3 years ago
Help with this physics question please :)
irina [24]

Answer:

is that rm in you profile pic

4 0
3 years ago
A 1500 kg car carrying four 90 kg people travels over a "washboard" dirt road with corrugations 3.7 m apart. The car bounces wit
umka21 [38]

Answer:

Car body rise on its suspension by 0.0309 m

Explanation:

We have given mass of the car m = 1500 kg

Mass of each person = 90 kg

Speed of the car v=20km/hr=20\times \frac{5}{18}=5.555m/sec

Distance traveled by car d = 3.7 m

So time period  T=\frac{distance}{speed}=\frac{4}{5.55}=0.72sec

Frequency f=\frac{1}{T}=\frac{1}{0.72}=1.388Hz

Angular frequency is \omega =2\pi f=2\times 3.14\times 1.388=8.722rad/sec

Angular frequency is equal to \omega =\sqrt{\frac{k}{m}}

8.722 =\sqrt{\frac{k}{1500}}

k = 114109.92 N/m

Now weight of total persons will be equal to spring force

4mg=kx

4\times 90\times 9.8=114109.92\times x

x = 0.0309 m

7 0
3 years ago
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