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saw5 [17]
3 years ago
7

NEED HELP BEFORE 12 please

Mathematics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

i to You help yes You help me ok?

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H(x) = x2 1 k(x) = x – 2 (h k)(2) = (h – k)(3) = Evaluate 3h(2) 2k(3) =.
natima [27]

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.The value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

<h3>Given information-</h3>

The given function is,

h(x)=x^2+1

k(x)=x-2

<h3>Quadratic equation</h3>

Quadratic equation is the equation in which only one variable is unknown. The highest power of the variable is 2.

1) The value of the function (h+k)(2),

(h+k)(x)=h(x)+k(x)

(h+k)(x)=x^2+1+x-2

(h+k)(2)=2^2+1+2-2

(h+k)(x)=5

2)The value of the function (h-k)(3),

(h-k)(x)=h(x)-k(x)

(h-k)(x)=x^2+1-x+2

(h-k)(3)=3^2+1-3+2

(h-k)(x)=9

3) The value of the function 3h(2)+2k(3)

3h(x)+2k(x)=3x^2+3+2x-2\times 2

3h(2)+2k(3)=3\times2^2+3+2\times2-2\times 2

3h(2)+2k(3)=17

Hence the value of the given functions are,

(h+k)(x)=5

(h-k)(x)=9

3h(2)+2k(3)=17

Learn more about the quadratic equation here;

brainly.com/question/2263981

4 0
2 years ago
What is 1.147 , 1.15 , 1.098 , 0.884 from greatest to least
SOVA2 [1]
1.15,1.147,1.098,.884
5 0
3 years ago
Read 2 more answers
10.
laila [671]

Answer:

Dave bought the clock for $300. Each year the value of the clock increased by $50.

Step-by-step explanation:

6 0
2 years ago
2x(squared) + 23x-19=0
Helen [10]
Use quadratic formula

for ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

given
2x^2+23x-19=0
a=2
b=23
c=-19

x=\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}
x=\frac{-23+/- \sqrt{529-152} }{4}
x=\frac{-23+/- \sqrt{377} }{4}

x=\frac{-23+ \sqrt{377} }{4} or \frac{-23- \sqrt{377} }{4}
7 0
3 years ago
Please Help !!!!!!!!!!!!!!
TEA [102]

Answer:

27

Step-by-step explanation:

643-166=477

477÷18=26.5

Then, round to the nearest whole.

Which makes it 27 sets.

7 0
3 years ago
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