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agasfer [191]
2 years ago
13

HCI + NaOH --> NaCl + H 20

Chemistry
1 answer:
Vikki [24]2 years ago
6 0

Answer:

option D is correct

Explanation:

no of moles in 3 grams of HCL=3/36=0.08

if 1 mole of HCL require 1 mole of NaOH then 0.08 moles required 0.08 moles of NaOH

mass of 0.08 moles of NaOH=moles*molar mass=0.08*40=3.2 grams

so 3 grams are required in the reaction

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A laser used to read CDs emits red light of wavelength 700 nm. How many photons does it emit each second if its power is?(a) 0.1
Elenna [48]

power = work/time

watt = joule/sec

a) power = 0.10 watt = 0.1joules/sec

work = power * time

= 0.10 * 1 =0.1joules

work is northing but energy

therefore energy is 0.1joules

according to planks quantum theory E = nhν where nis the no. of photons ; h is planks constant; ν isfrequency

hence, n = E/hν

or n = Eλ/hc (ν = c/λ)

n = (0.1*700*10^-9)/6.625*10^-34*3*10^8 = 0.3522*10^18photons

b) similar to the above calculation

here E = 1.0joules

n = (1.0*700*10^-9)/6.625*10^-34*3*10^8 = 0.3522*10^17photons

4 0
3 years ago
If a chemical reaction such as photosynthesis begins with 6 atoms of carbon C , how many atoms of carbon C should be in the prod
lara [203]

Answer:

Option B. 6 atoms of carbon

Explanation:

In <u><em>any chemical reaction</em></u>, atoms from reactant side and product side must be the same.

This is photosynthesis reaction:

6CO₂  + 6H₂O  →  C₆H₁₂O₆  +  6O₂

8 0
3 years ago
How many milliliters of 0.500 M NaOH should be added to 10.0 g of tris hydrochloride (FM 121.135) to give a pH of 7.60 in a fina
liubo4ka [24]

Answer:

41.64mL of NaOH 0.500M must be added to obtain the desire pH

Explanation:

It is possible to find pH of a buffer by using H-H equation, thus:

pH = pka + log [A⁻] / [HA]

<em>Where [HA] is concentration of the weak acid TRIS-HCl and [A⁻] is concentration of its conjugate acid.</em>

Replacing in H-H equation:

7.60 = 8.072 + log [A⁻] / [HA]

0.3373 =  [A⁻] / [HA] <em>(1)</em>

10.0g of TRIS-HCl (Molar mass: 121.135g/mol) are:

10.0g ₓ (1mol / 121.135g) = 0.08255 moles of acid. That means moles of both the acid and conjugate base are:

[A⁻] + [HA] = 0.08255 <em>(2)</em>

Replacing (1) in (2):

0.3373 =  0.08255 - [HA] / [HA]

0.3373[HA] =  0.08255 - [HA]

1.3373[HA] = 0.08255

<em>[HA] = 0.06173 moles</em>

Thus:

[A⁻]  = 0.08255 - 0.06173 = 0.02082 moles [A⁻]

The moles of A⁻ comes from the reaction of the weak acid with NaOH, that is:

HA + NaOH → A⁻ + H₂O + K⁺

Thus, <em>you need to add 0.02082 moles of NaOH to produce 0.02082 moles of A⁻. </em>As NaOH solution is 0.500M:

0.02082 moles NaOH ₓ (1L / 0.500mol) = 0.04164L of NaOH 0.500M =

<h3>41.64mL of NaOH 0.500M must be added to obtain the desire pH</h3>

3 0
3 years ago
Calorimeter containing 1000 grans of water the initial temperature of water is 24.85 degrees . the heat of water is 4.184 j/g de
kvasek [131]
<h3><u>Answer;</u></h3>

10.80 ° C

<h3><u>Explanation;</u></h3>

From the information given;

Initial temperature of water =  24.85°C

Final temperature of water = 35.65°C

Mass of water = 1000 g

The specific heat of water ,c = 4.184 J/g °C.

The heat capacity of the calorimeter  = 695 J/ °C

Change in temperature ΔT = 35.65°C - 24.85°C

                                             = 10.80°C

3 0
3 years ago
What is the mass measurement shown on the scales of this balance?
otez555 [7]
The answer is definitely not 70.923
6 0
3 years ago
Read 2 more answers
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