After the full moon, the moon begins its shrinking or_phases. During these phases, the light side of the moon is on the_
1 answer:
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Answer:
Amplitude will be equal to 0.091 m
Explanation:
Given mass of the slits = 41 gram = 0.041 kg
Frequency f = 1.65 Hz
So angular frequency
Angular frequency is equal to
Squaring both side
k = 4.40 N/m
For vertical osculation
A = 0.091 m
So amplitude will be equal to 0.0391 m
Answer:
Explanation:
Given:
mass of ice melted,
time taken by the ice to melt,
latent heat of the ice,
Now the heat rejected by the Carnot engine:
Since we have boiling water as hot reservoir so:
The cold reservoir is ice, so:
Now the efficiency:
Now form the law of energy conservation:
Heat supplied:
where:
heat supplied to the engine
Now the work done:
Answer:
speed of a particle = 2.31 × m/s
energy of proton required = 27.77 KeV
energy of electron required = 15.171 eV
Explanation:
given data
magnetic field of magnitude = 0.22 T
electric field of magnitude = 0.51 MV/m
to find out
speed of a particle and energy must protons have to pass through undeflected and energy must electrons have to pass through undeflected
solution
we know that force due to magnetic and electric field is express as
force due to magnetic field B = qvB ..............1
and force due to electric field E = qE .....................2
so without deflection force due to magnetic field = force due to electric field
so here qvB = qE
and V = ...................3
put here value
V =
speed of a particle = 2.31 × m/s
and
now energy of proton required will be here as
energy of proton required = mass of proton ×
put here value
energy of proton required = 1.67 × ×
energy of proton required = 4.45 × J
energy of proton required = 4.45 × J ÷ (1.602 ×
energy of proton required = 27777.777 eV
energy of proton required = 27.77 KeV
and
now we get here energy of electron required that is
energy of electron required = mass of electron ×
put here value
energy of electron required = 9.11 × ×
energy of electron required = 24.305× J
energy of electron required = 24.305 × J ÷ (1.602 ×
energy of electron required = 15.171 eV