Answer:
4.68227 °C
Explanation:
= Mass of object = 500 kg
= Mass of water = 25 kg
c = Specific heat of water at 20°C = 4186 J/kg°C
h = Height from which the object falls = 100 m
g = Acceleration due to gravity = 9.8 m/s²
The potential energy and heat will balance each other
The temperature change in the water is 4.68227 °C
Answer:
<h2>206.67N</h2>Explanation:
The sum of force along both components x and y is expressed as;
The magnitude of the net force which is also known as the resultant will be expressed as
To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.
Given the position of the object along the x-component to be x = 6t² − 4;
Similarly,
Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N