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NARA [144]
3 years ago
14

After the full moon, the moon begins its shrinking or_phases. During these phases, the light side of the moon is on the_

Physics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0
I believe the answer is b
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The tilt of the earth on its axis causes the seasons.
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All points to the blank of zero on a horizontal number line are negative.
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All points to the left of zero on a horizontal number line are negative. A  number line<span> is a picture of a graduated straight </span>line<span> that serves as abstraction for real </span>numbers. <span>This </span>number line<span> can be extended to the left to </span>represent numbers<span> which are smaller than </span>0<span>. Such </span>numbers<span> are called negative </span>numbers<span>.</span>
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How and why does the distance between 2 electrodes affect the rate of electrolysis? ...?
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 <span>Nothing, in terms of the chemistry. 

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4 0
3 years ago
A solid wood door 1.00 m wide and 2.00 m high is hinged along one side and has a total mass of 40.0 kg. Initially open and at re
xxTIMURxx [149]

Answer:

The final angular speed is 0.223 rad/s

Explanation:

By the conservation of angular moment:

ΔL=0

L₁=L₂

L₁ is the initial angular moment

L₂ is the final angular moment

L₁ is given by:

L_1=L_{door} + L_{mud}

As the door is at rest its angular moment is zero and the angular moment of mud can be considered as a point object, then:

L_1= L_{mud}= mvr

where

r is the distance from the support point to the axis of rotation (the mud hits at the center of the door; r=0.5 m)

v is the speed

m is the mass of the mud

L₂ is given by:

L_2= (I_{door} + I_{mud}) \omega_f

ωf is the final angular speed

The moment of inertia of the door can be considered as a rectangular plate:

I_{door}=\frac{1}{3}MW^2

M is the mass of the door

W is the width of the door

The moment of inertia of the mud is:

I_{mud}=mr^2

Hence,

L_1=L_2\\mvr= (I_{door} + I_{mud}) \omega_f\\\omega_f=\frac{mvr}{I_{door} + I_{mud}} \\\omega_f=\frac{mvr}{I_{door} + I_{mud}}

\omega_f=\frac{0.5kg \times 12m/s \times 0.5m}{\frac{1}{3}40kg(1m)^2+0.5kg \times (0.5m)^2}

\omega_f=0.223 \frac{rad}{s}

6 0
4 years ago
I need help thank you​
Brums [2.3K]

Answer:

D

Explanation:

3 0
3 years ago
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