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Delvig [45]
3 years ago
7

Define the meaning of the phrase entry requirements to higher education insulations and state four reasons why knowing the entry

requirements is important.​
Physics
1 answer:
Arada [10]3 years ago
8 0
It's the gravity of the space lagoon
You might be interested in
Three ideal polarizing filters are stacked, with the polarizing axis of the second and third filters at 21 degrees and 61 degree
kvv77 [185]

Answer:

1

When second polarizer is removed the intensity after it passes through the stack is    

                    I_f_3 = 27.57 W/cm^2

2 When third  polarizer is removed the intensity after it passes through the stack is    

                I_f_2 = 102.24 W/cm^2

Explanation:

  From the question we are told that

       The angle of the second polarizing to the first is  \theta_2 = 21^o  

        The angle of the third  polarizing to the first is     \theta_3 = 61^o

        The unpolarized light after it pass through the polarizing stack   I_u = 60 W/cm^2

Let the initial intensity of the beam of light before polarization be I_p

Generally when the unpolarized light passes through the first polarizing filter the intensity of light that emerges is mathematically evaluated as

                     I_1 = \frac{I_p}{2}

Now according to Malus’ law the  intensity of light that would emerge from the second polarizing filter is mathematically represented as

                    I_2 = I_1 cos^2 \theta_1

                       = \frac{I_p}{2} cos ^2 \theta_1

The intensity of light that will emerge from the third filter is mathematically represented as

                  I_3 = I_2 cos^2(\theta_2 - \theta_1 )

                          I_3= \frac{I_p}{2}(cos^2 \theta_1)[cos^2(\theta_2 - \theta_1)]

making I_p the subject of the formula

                  I_p = \frac{2L_3}{(cos^2 \theta [cos^2 (\theta_2 - \theta_1)])}

    Note that I_u = I_3 as I_3 is the last emerging intensity of light after it has pass through the polarizing stack

         Substituting values

                      I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (61-21)])}

                      I_p = \frac{2 * 60 }{(cos^2(21) [cos^2 (40)])}

                           =234.622W/cm^2

When the second    is removed the third polarizer becomes the second and final polarizer so the intensity of light would be mathematically evaluated as

                      I_f_3 = \frac{I_p}{2} cos ^2 \theta_2

I_f_3 is the intensity of the light emerging from the stack

                     

substituting values

                     I_f_3 = \frac{234.622}{2} * cos^2(61)

                       I_f_3 = 27.57 W/cm^2

  When the third polarizer is removed  the  second polarizer becomes the

the final polarizer and the intensity of light emerging from the stack would be  

                  I_f_2 = \frac{I_p}{2} cos ^2 \theta_1

I_f_2 is the intensity of the light emerging from the stack

Substituting values

                  I_f_2 =  \frac{234.622}{2} cos^2 (21)

                     I_f_2 = 102.24 W/cm^2

   

7 0
3 years ago
A helicopter’s speed increases from 30 m/s to 40 m/s in 5 seconds.
TEA [102]
Acceleration is defined as the rate of change of velocity, which, simply put, is a mouthful to describe how fast something speeds up, slows down, or turns. The equation for acceleration is

a = Δv / Δt,

or your final velocity - your starting velocity, then divided by the amount of time. It can also be expressed as

a = (Vf - Vi) / t,

Where Vf is your final velocity, Vi is your initial velocity, and t is the time traveled.

The question gives us that the helicopter moves from a starting velocity of 30 m/s to a final velocity of 40 m/s in the span of 5 seconds. This means we can fill in the variables to the equation, where

Vf = 40,
Vi = 30, and
t = 5.

Plug these known variables into the original equation, and we get

a = (Vf - Vi) / t = (40 - 30) / 5.

From here, the answer comes down to 10 / 5, or 2 m/s^2.

Hope this helps! If you have any questions, don't hesitate to ask :D
6 0
4 years ago
Read 2 more answers
Discuss how the passage of time can affect the brain ? , comment on how human memory works or doesn't work. include memory kids
sergiy2304 [10]

Answer:

the stored memory undergoes important changes, as revealed by the behavioral outcomes of its retrieval.

Explanation:

6 0
3 years ago
When you drop a 0.37kg apple earth exerts a force on it that accelerates it at 9.8m/s^2 toward the earths surface. According to
Delvig [45]

force applied due to earth on the apple is given as

F = ma

given that

m = 0.37 kg

a = 9.8 m/s^2

now we have

F = m*a

F = 0.37* 9.8 = 3.63 N

now as per Newton's III law equal and opposite force is applied on earth

so now we can find acceleration of Earth using same equation as we used above

F = ma

here we know that

m = mass of earth

F = 3.63 N

3.63 = 5.98 * 10^{24} * a

a = \frac{3.63}{5.98 * 10^{24}

a = 6.1 * 10^{-25} m/s^2

so acceleration of earth is very small and given by above value

5 0
3 years ago
When the temperature of air rises, the amount of water needed for saturation
Oliga [24]
It Increases. I just took a quiz with the same question.
7 0
4 years ago
Read 2 more answers
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