Answer:
Radial force component of force = 37.68 N
Explanation:
By Newton's 2 nd law of motion,
F = ma
F = 3.0 N, m = 0.5 Kg, a (Linear Acceleration ) = ?
3 = 0.5 a
a = 6
Now, a = 6 , r = 2.5 m ,α(angular acceleration ) = ?
a = r α
6= 2.5 α
hence α = 2.4 rad/
we know that,
Radial force component of force =
since m =0.5 kg, r =2.5 m w =5.49 rad/sec
Radial force component of force = = 37.68 N
When an object is moving around in circles, there are two forces that keeps it in its circular orbit. These are the centripetal and the centrifugal forces. They are equal in magnitude, but they differ in the direction. The centripetal force is the force that pulls the object toward the circle's center. The centrifugal force is the force that pushed the object away from the circle's center.
Applying Newton's Second Law of Motions, any force is equal to its mass times its acceleration. For an object moving in circles, the force here is centrifugal or centripetal force, and the acceleration is the centripetal or centrifugal acceleration which is equal to
a = v²/r,
where v is the linear or tangential velocity
r is the radius of the circle
Applying this to Newton's Second Law of Motion,
F = mv²/r
Substituting the values,
F = (1,520 kg)(24 m/s)²/455 m
F = 1,924.22 N
The phenomenon of "weightlessness" occurs when there is no force of support on your body. When your body is effectively in "free fall", accelerating downward at the acceleration of gravity, then you are not being supported.
Answer:
Acceleration acts always in the direction. Of the displacement. Of the initial velocity.