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ioda
2 years ago
9

The mass of 25cm of ivory was found to be 0.045kg. caculate the density of ivory in SI units​

Physics
1 answer:
solmaris [256]2 years ago
7 0

Answer:

dgdhvjgfjfdcdrtdgxbhjcdtsdhcbgtdytfgiuftrshdryrgbiuwdbcuhdds

Explanation:

,ajsgfgsdfubcygduhdsbcdshyudbckjdshfyendhdndbhfdbuehundweugdjnbfcjdfhewjdnbewqwioehsajcnbsfhhgjhbgjhhbjdhgwbvdwnjjguhbwqhjbsjwqhshwbdjagdasndhsajuwqbdjasnjashdjaskxnjgjjsklx ms,dhwshjksnjdbhjssnj,

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A 60 Watt light bulb runs for 120 seconds. How much energy does it use?
sattari [20]
ENERGY = POWER X TIME
=60 X 120=7200KWh
6 0
3 years ago
a 0.15 kg baseball has a momentum of 0.78 kg*m/s just before it lands on the ground. What was the ball's speed just before landi
vovangra [49]

5.2m/s

Explanation:

Given parameters:

Mass of baseball = 0.15kg

Momentum of baseball = 0.78kgm/s

Unknown:

Speed of baseball = ?

Solution:

The momentum of the baseball is a function of the product of the mass and velocity. It is a vector quantity:

        Momentum = mass x velocity

 Since the speed of the ball is unknown:

           Velocity  =  \frac{momentum }{mass}

                           = \frac{0.78}{0.15}

                           = 5.2m/s

The speed of the baseball before it lands is 5.2m/s

Learn more:

Momentum brainly.com/question/9484203

#learnwithBrainly

4 0
3 years ago
Electrons are negatively charged, protons are positively charged that makes neutrons what charge
Naddik [55]
Neutral - they have mass but no charge
5 0
2 years ago
Read 2 more answers
What the Ph measures??
Elenna [48]
PH measures the concentration of hydrogen ions (H^{+}) in a solution. Knowing this, you can determine how acidic -or basic- your solution is.
5 0
3 years ago
As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arr
Natalija [7]

Answer:

a) F = 680 N, b)  W = 215 .4 J , c)  F = 1278.4 N

Explanation:

a) Hooke's law is

              F = k x

To find the displacement (x) let's use the elastic energy equation

            K_{e} = ½ k x²

             k = 2 K_{e}  / x²

             k = 2 85.0 / 0.250²

             k = 2720 N / m

We replace and look for elastic force

            F = 2720  0.250

            F = 680 N

b) The definition of work is

          W = ΔEm

          W = K_{ef} - K_{eo}

          W = ½ k ( x_{f}² - x₀²)

The final distance

         x_{f} = 0.250 +0.220

        x_{f} = 0.4750 m

We calculate the work

          W = ½ 2720 (0.47² - 0.25²)

          W = 215 .4 J

We calculate the strength

          F = k x_{f}

          F = 2720 0.470

          F = 1278.4 N

6 0
2 years ago
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