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3 years ago

What is the mass of an object if a force of 34 N produces an acceleration of 4 m/s^2?

Physics

2 answers:

Paha777 [63]3 years ago

8 0

F=ma

F/a=m

34/4 =8.5

8.5 kilograms

Westkost [7]3 years ago

8 0

Answer:

Mass of the object is 8.5 kg.

Explanation:

Given that,

Acceleration of the object is 4 m/s^2

Force applied to the object, F = 34 N

To find :

The mass of the object.

Solve :

Let m is the mass of the ball. The Newton's second law of motion defines the magnitude of force acting on an object.

$F=ma$

$m=\dfrac{F}{a}$

$m=\dfrac{34\ N}{4\ m/s^2}$

m = 8.5 kg

Therefore, the mass of the ball is 8.5 kg.

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3 years ago

Three capacitors having capacitances of 8.40, 8.40, and 4.20 μFμF, respectively, are connected in series across a 36.0-V potenti

son4ous [18]

Answer:

a)Q=71.4 μ C

b)ΔV' = 10.2 V

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Given that

C ₁= 8.7 μF

C₂ = 8.2 μF

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The potential difference of the battery, ΔV= 34 V

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1/C = 1/C ₁ + 1/C₂ + 1/C₃

1/ C= 1/8.4 +1 / 8.4 + 1/4.2

C=2.1 μF

As we know that when capacitor are connected in series then they have same charge,Q

Q= C ΔV

Q= 2.1 x 34 μ C

Q=71.4 μ C

As we know that when capacitor are connected in parallel then they have same voltage difference.

Q'= C' ΔV'

C'= C ₁+C₂+C₃ (For parallel connection)

C'= 8.4 + 8.4 + 4.2 μF

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Q'= C' ΔV'

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3 years ago

14. If the spring constant of a simple harmonic oscillator is doubled, by what factor will the mass of the system need to change

klio [65]

Lets se

And

$\\ \rm\Rrightarrow T=2\pi\sqrt{\dfrac{m}{k}}$

$\\ \rm\Rrightarrow \sqrt{k}T=2\pi\sqrt{m}$

$\\ \rm\Rrightarrow k\propto m$

If spring constant is doubled mass must be doubled

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2 years ago

A 6.5 x 104 W engine exerts a constant force on of 5.5 x 103 N on a car, the resulting velocity is?

jek_recluse [69]

Answer:

12m/s

Explanation:

Given parameters:

Power = 6.5 x 10⁴W

Force = 5.5 x 10³N

Unknown:

The resulting velocity = ?

Solution:

The velocity of a body is related to force and power using the expression below;

Power = Force x velocity

Insert the parameters and solve for velocity

6.5 x 10⁴ = 5.5 x 10³ x velocity

velocity = $\frac{6.5 x 10^{4} }{5.5 x 10^{3} }$ = 12m/s

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2 years ago