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Rama09 [41]
2 years ago
9

explain why using a parabolic mirror for a car headlight throws much more light on the highway than a flat mirror.

Physics
1 answer:
Murrr4er [49]2 years ago
6 0

Answer:

The rays do not polarize after reflection. The rays are dispersed after reflection. The rays are polarized after reflection.

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Answer this please nowww
Viefleur [7K]
(3) The frictional force exerted by the floor on the box
4 0
3 years ago
A 9.5 V battery supplies a 3.5 mA current to a circuit for 7.0 h. Part A How much charge has been transferred from the negative
pychu [463]

Answer:

88.2 C

Explanation:

The current can be defined as the rate of flow of charge in a conductor.

The relation between charge current and time is given as

I = Q/T

I = current, Q= charge and T = time

that is ampere = coulomb / second

The amount of charge passed is from the negative to the positive terminal

shall be given by:

Q = I * t = 3.5mA * 7h * 3600s/h = 88.2 C

Note: take care of the units.  

7 0
3 years ago
What are four characteristics of environments near the shore?
Dimas [21]

Answer I don’t knows

Explanation: i don’t know I just want points

3 0
3 years ago
Read 2 more answers
You throw a small rock straight up from the edge of a highway bridge that crosses a river. the rock passes you on its way down,
maw [93]
V^2=u^2 +2aS
U is found first by considering that first 8 secs and using v=u+at. {different v and u though}

V=-u+gt.
Magnitude of u = magnitude of v if there is no resistance ( because the conservation of energy says the k. E. must be the same when it passes you as when it left your hand).... up is negative here, down is positive.
V+v=gt
2v= g x 8
V=4xg.= the initial velocity for the next calculation
V^2=(4g)^2+(2xgx21)

So v can be calculated.

4 0
3 years ago
Provided the amplitude is sufficiently great, the human ear can respond to longitudinal waves over a range of frequencies from a
riadik2000 [5.3K]

Answer:

Check the explanation

Explanation:

The beat frequency is

df = f2 - f1

the wavelength is

lamda1 = (v/f1)

and lamda2 = (v/f2)

where v = 340 m/s,f1 = 25.0 kHz and f2 = 20.0 kHz

8 0
2 years ago
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