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saveliy_v [14]
3 years ago
15

List factors that make the bonding of carbon atoms unique.

Chemistry
1 answer:
solniwko [45]3 years ago
7 0

Answer:

yessirrrrrrrrrrrrrr

Explanation:lets get ma boa

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How many grams are in 1 mole of Pb3(PO4)4?
kvasek [131]

Answer:

In 1 mol of Pb₃(PO₄)₄ occupies 1001.48 grams

Explanation:

This compound is the lead (IV) phosphate.

Grams that occupy 1 mole, means the molar mass of the compound

Pb = 207.2  .3 = 621.6 g/m

P = 30.97 .4 = 123.88 g/m

O = (16 .  4) . 4 = 256 g/m

621.6 g/m + 123.88 g/m + 256 g/m = 1001.48 g/m

6 0
2 years ago
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Revolver features several firing chambers located within...
Blizzard [7]

Answer:

What are the characteristics of a revolver?

Explanation:

The revolver features several firing chambers located within a revolving cylinder. The cylinder rotates as the revolver is fired, lining up each bullet mechanically.

8 0
2 years ago
Which organism has a nerve net? A fish B hydra C flatworm D sponge
Kaylis [27]
B. Hydra, because Hydra<span>are an ideal class of </span>Cnidaria<span> to research and on which to run tests.</span>
5 0
2 years ago
Read 2 more answers
You measure the emission spectrum of an atom that you suspect to be hydrogen. You have no absolute calibration of the wavelength
trapecia [35]

Answer:

Explanation:

What we need to do here is to determine the ratios by using  the Rydberg equation starting with the transition to n1 = 1, 2,3, etc and see which one fits the data. Remember the question states that they are series and the wavelengths will be for increasing  energy levels.

1/λ = Rh x ( 1/n₁² - 1/n₂²)

Lyman series  ( n₁=1 and n₂= 2,3 etc)  for the first two lines, the ratios will be:

1/λ₁ /1/λ₂  =(1/1 -1/ 2²) / (1/1 -1/ 3²) ⇒ 0.84 ≠ 0.74  (the first ratio)

For Balmer series n₁ = 2  and n₂ = 3,4,5, etc

1/λ₁ /1/λ₂  =(1/4 -1/3²) / (1/4 -1/4²) ⇒ 0.741 = 0.741 (match!)

Lets use the third line to check our answer:

1/λ₁ /1/λ₂  =(1/4 -1/3²) / (1/4 -1/5²) = 0.66

5 0
3 years ago
What is the molarity of a solution that is made by mixing 35.5 g of Ba(OH)2 in 325 ml of solution?
choli [55]

Answer:

M=0.638M

Explanation:

Hello!

In this case, since the molarity of a solution is calculated by diving the moles of solute by the volume of solution in liters, we first compute the moles of barium hydroxide in 35.5 g as shown below:

n=35.5g Ba(OH)_2*\frac{1molBa(OH)_2}{171.34gBa(OH)_2}\\\\n=0.207mol

Then, the liters of solution:

V=325mL*\frac{1L}{1000mL} =0.325L

Finally, the molarity turns out:

M=\frac{0.207mol}{0.325L}\\\\M=0.638M

Best regards!

5 0
3 years ago
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