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NNADVOKAT [17]
3 years ago
12

A car has a mass of 550 kg. What is the weight of the car?

Physics
2 answers:
lozanna [386]3 years ago
3 0
1212.54 is what 550 kgs is equal to the weight of the car
ExtremeBDS [4]3 years ago
3 0

<u>Answer:</u> The weight of the car is 5390 N

Explanation:

Weight is defined as the force exerted by the body on any surface. It is also defined as the product of mass of the body multiplied by the acceleration due to gravity.

Mathematically,

W=mg

where,

W = weight of the car

m = mass of the car = 550 kg

g = acceleration due to gravity on Earth = 9.8m/s^2

Putting values in above equation, we get:

W=550kg\times 9.8m/s^2=5390N

Hence, the weight of the car is 5390 N

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A cell supplies current of 0.6A and 0.2A through 1ohms and 4.0ohms resistor respectively. Calculate the internal resistance of t
Vlad [161]
<h2>Answer:</h2>

0.5Ω

<h2>Explanation:</h2>

Since different currents are passing through the resistors, then the resistors are most probably connected in parallel. This also means that the same voltage will pass across them.

Using Ohm's law, the voltage across a resistor in a circuit is given by;

V = I(R + r)            -----------(i)

<em>For the 1ohm resistor, the voltage across it is given by;</em>

<em>Where;</em>

I = current passing through the 1 ohm resistor = 0.6A

R = resistance of the 1 ohm resistor = 1Ω

r = internal resistance of the cell = r

Substitute these values into equation (i) as follows;

V = 0.6(1 + r)                 -------------------(ii)

<em>For the 4.0ohm resistor, the voltage across it is given by;</em>

<em>Where;</em>

I = current passing through the 4.0 ohms resistor = 0.2A

R = resistance of the 4.0 ohms resistor = 4.0Ω

r = internal resistance of the cell = r

Substitute these values into equation (i) as follows;

V = 0.2(4.0 + r)                 -------------------(iii)

<em>Now solve equations (ii) and (iii) simultaneously;</em>

V = 0.6(1 + r)

V = 0.2(4.0 + r)

Substitute the value of V in equation (ii) into equation (iii). Therefore, we have;

0.6(1 + r) = 0.2(4.0 + r)

<em>Solve for r</em>

0.6 + 0.6r = 0.8 + 0.2r

0.6r - 0.2r = 0.8 - 0.6

0.4r = 0.2

r = \frac{0.2}{0.4}

r = 0.5

Therefore, the internal resistance of the cell is 0.5Ω

4 0
3 years ago
A 1.5 kg ball pushed with a force of 13.5 N accelerates to the left. What is the acceleration of the ball?​
GarryVolchara [31]

Explanation:

F= ma

13.5 =1.5a

1.5a/1.5 =13.5/1.5

a= 9 m/s^2

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