Answer:
2 if u are doing what i think u are doing
Answer:
"The number of air molecules above a surface determines air pressure. As the number of molecules increases, they exert more pressure on a surface, and the total atmospheric pressure increases. By contrast, if the number of molecules decreases, so too does the air pressure."
Since the equation for density is d=m/v, you can multiply both sides by m in order to get m by itself {d(v)=m}. Plug the volume and density in (1.1x7.9) and you will get 8.69. If you are using proper sig figs, then it will be 8.7g.
Answer:
Part A:
Order: K<Rb<Cs
Part B:
Order: O<C<Be
Part C:
Order:CL<S<K
Part D:
Order:Mg<Ca<K
Explanation:
Atomic Size:
It is the distance from the center to atom to the valance shell electron. It is very difficult to measure the atomic size because there is definite boundary of atom.
Trend:
Moving from top to bottom in a group, Atomic Size increases.
Moving from left to right in a period, Atomic size generally decreases.
On the basis of above trend we will solve our question:
Part A:
All elements belong to Group 1:
Moving from top to bottom in a group, Atomic Size increases.
Order: K<Rb<Cs
Part B:
All elements belong to 2nd Period:
Moving from left to right in a period, Atomic size generally decreases.
Order: O<C<Be
Part C:
S belongs to 3rd Period, K, Cl belong to 4th period
Order:CL<S<K
Part D:
Mg is above Ca in group 2 and K is before Ca in 4th period
From trends described above:
Order:Mg<Ca<K
Answer:
I believe it would be C or B