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Katen [24]
3 years ago
8

What are the units for electric current

Physics
1 answer:
Anettt [7]3 years ago
3 0

Answer:

B) Amps

Which are called Ampere or Amp.

Explanation:

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Yes, an object<span> that was set in motion in the past by some force, but that is no longer being acted on by a net force, is </span>moving<span> but with </span>zero acceleration<span>, i.e. it is </span>moving<span> at constant velocity.</span>
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In which situation is chemical energy being converted to another form of energy?
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<span>D. A burning candle. (chemical energy into energy of heat and light, i.e. thermal and wave)</span>
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How many normal modes of oscillation or natural frequencies does each if the following have: (
Vadim26 [7]
<span>Each of these systems has exactly one degree of freedom and hence only one natural frequency obtained by solving the differential equation describing the respective motions. For the case of the simple pendulum of length L the governing differential equation is d^2x/dt^2 = - gx/L with the natural frequency f = 1/(2π) √(g/L). For the mass-spring system the governing differential equation is m d^2x/dt^2 = - kx (k is the spring constant) with the natural frequency ω = √(k/m). Note that the normal modes are also called resonant modes; the Wikipedia article below solves the problem for a system of two masses and two springs to obtain two normal modes of oscillation.</span>
6 0
3 years ago
An unknown fluid has a specific gravity of 0.750. What is the volume of 22.5 kg of this fluid?
Andru [333]
<h2>Option C is the correct answer.</h2>

Explanation:

Specific gravity of fluid = 0.750

Density of fluid = Specific gravity of fluid x Density of water

Density of fluid = 0.750 x 1000

Density of fluid = 750 kg/m³

Mass of fluid = 22.5 kg

We have

         Mass = Volume x Density

         22.5 = Volume x 750

         Volume = 0.03 m³ = 30 L

Option C is the correct answer.

5 0
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A car travels along a clear 10.0 km section of motorway in 6.0 minutes. It then drives through 3.0 km of roadwork in 3.0 minutes
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  • 6min=1/10h=0.1h
  • 3min=1/20h=0.05h

\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{Total\:Displacement}{Total\:Time}

\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{10+3}{0.1+0.05}

\\ \bull\tt\dashrightarrow Avg\:Speed=\dfrac{13}{0.15}

\\ \bull\tt\dashrightarrow Avg\:Speed=86.6km/h

5 0
2 years ago
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