Answer:
36.22 mA
Explanation:
i1 = I , i2 = I, d = 8.2 cm = 0.082 m
Force per unit length = 3.2 nN/m = 3.2 x 10^-9 N/m
μo = 4 π × 10^-7 Tm/A
The formula for the force per unit length between the two wires is given by
F = μo / 4π x (2 i1 x i2) / d
3.2 x 10^-9 = 10^-7 x 2 x I^2 / 0.082
I = 0.0362 A = 36.22 mA
Hi there!
Recall the equation for electric potential of a point charge:

V = Electric potential (V)
k = Coulomb's Constant(Nm²/C²)
Q = Charge (C)
r = distance (m)
We can begin by solving for the given electric potentials. Remember, charge must be accounted for. Electric potential is also a SCALAR quantity.
Upper right charge's potential:

Lower left charge's potential:

Add the two, and subtract from the total EP at the point:

The remaining charge must have a potential of 2036.25 V, so:

E=hf C=wavelength*F
E=hC/wavelength
E=(6.626*10^-34)*(3.00*10^8)/670*10^-9
E=(6.626*10^-34)*(3.00*10^8)/450*10^-9
The average speed is 52km