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vladimir1956 [14]
3 years ago
6

What is the average speed of an object with a total distance traveled of 45 meters in 50 seconds

Physics
1 answer:
Anettt [7]3 years ago
7 0

Answer: 0.9m/s

Explanation:

Use equation for speed:

V=S/t

S-distance; S=45m

t-time; t=50 s

V=S/t

V=45m/50s

V=0.9 m/s

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Ac soucre change it polarity how many time
Karolina [17]
Alternating current (AC) flows half the time in one direction and half the time in the other, changing its polarity 120 times per second with 60-hertz current.
6 0
3 years ago
Fe₂O3<br> + co<br> →<br> Fe3O4 + CO₂
Goryan [66]

Explanation:

                    Fe₂O₃  + CO  → Fe₃O₄ + CO₂

Balancing the equation above, we can derive simple mathematical equations that are very easy to solve.

             aFe₂O₃  + bCO  → cFe₃O₄ + dCO₂

a,b,c and d are the coefficients needed to balance the equation above;

  Conserving Fe; 2a = 3c

                       O: 3a + b = 4c + 2d

                        C: b = d

 let a = 1;

      c = \frac{2}{3}

      Since b = d

                  3a + d = 4c + 2d

                    3a = 4c + 2d - d

                     3a = 4c + d

           a = 1, c = \frac{2}{3}

                    3 = 4 x \frac{2}{3}  +  d

                   d = \frac{1}{3}

                    b = \frac{1}{3}

multiplying a, b, c and d by 3:

            a = 3    b = 1     c = 2   and d = 1

                  3Fe₂O₃  + CO  → 2Fe₃O₄ + CO₂

Learn more:

Balanced equation brainly.com/question/2612756

#learnwithBrainly

6 0
3 years ago
a train is moving with an initial velocity of 30 m/s, the brakes are applied so as to produce a uniform acceleration of -1.5 m/s
Pepsi [2]

Answer:

\boxed{\sf Time \ in \ which \ train \ will \ come \ to \ rest = 20 \ sec}

Given:

Initial velocity (u) = 30 m/s

Final speed (v) = 0 m/s

Acceleration (a) = - 1.5 m/,s²

To Find:

Time in which train will come to rest (t).

Explanation:

\sf From \ equation \ of \ motion: \\ \sf \implies \bold{v = u + at} \\ \\ \sf Substituting \ value \ of \ v, \ u \ and \ a:  \\  \sf \implies 0 = 30 + ( - 1.5)(t) \\   \sf  \implies 0 = 30 - 1.5(t) \\  \sf \implies 30 - 1.5(t) = 0 \\  \\  \sf Subtract  \: 30  \: from  \: both  \: sides: \\  \sf \implies (30 -  \boxed{ \sf 30}) - 1.5(t) =  \boxed{ \sf  - 30} \\  \\  \sf 30 - 30 = 0 :  \\  \sf \implies  - 1.5(t) =  - 30 \\  \\  \sf Divide  \: both  \: sides \:  of \:  - 1.5(t) =  - 30 \: by \:  - 1.5 :  \\  \sf \implies  \frac{  - 1.5(t)}{ \boxed{ \sf - 1.5}}  =  \frac{ - 30}{ \boxed{ \sf -1.5 }}  \\  \\  \sf \frac{ \cancel{ \sf 1.5}}{\cancel{ \sf 1.5}}  = 1 :  \\  \sf \implies t =  \frac{ - 30}{ - 1.5}  \\  \\   \sf  \frac{ - 30}{ - 1.5}  =  \frac{\cancel{ \sf 1.5} \times 20}{\cancel{ \sf 1.5}}  = 20 :  \\  \sf  \implies t = 20 \: sec

So,

Time in which train will come to rest = 20 seconds

4 0
3 years ago
The Hall effect can be used to calculate the charge-carrier number density in a conductor. A conductor carrying current of 2.0 A
marysya [2.9K]

Answer:

option D

Explanation:

given,

A conductor is carrying current = 2.0 A is 0.5 mm thick

Hall voltage = 4.5 x 10-6 V

uniform magnetic field  =  1.2 T

density of the charge = n =?

hall voltage =V_h =\dfrac{i\ B}{n\ e\ L}

n = \dfrac{i\ B}{V\ e\ L}

n = \dfrac{2 \times 1.2 }{4.5 \times 10^{-6}\times 1.6 \times 10^{-19} \times 0.5 \times 10^{-3}}

n = 6.67 × 10²⁷ charges/m

hence the correct answer is option D

7 0
3 years ago
Two astronauts are 2.00 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via electr
Eduardwww [97]

Answer:

D=1693742.7m

Explanation:

For sound waves we have v=d/t where v is the speed of sound and d the distance between the astronauts, while for electromagnetic waves we have c=D/t where c is the speed of light and D the distance between the spaceship and Earth. <em>We have written both times as the same</em> because is what is imposed by the problem, so we have t=d/v=D/c, which means:

D=\frac{dc}{v}

And for our values:

D=\frac{(2m)(299792458m/s)}{354m/s}=1693742.7m

5 0
3 years ago
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