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vladimir1956 [14]
3 years ago
6

What is the average speed of an object with a total distance traveled of 45 meters in 50 seconds

Physics
1 answer:
Anettt [7]3 years ago
7 0

Answer: 0.9m/s

Explanation:

Use equation for speed:

V=S/t

S-distance; S=45m

t-time; t=50 s

V=S/t

V=45m/50s

V=0.9 m/s

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Need answer fast plz
vazorg [7]

Answer:

a = 1.20m\s^{2}

Explanation:

225 x 9.8

= 441N

-

710 - 441

= 269N

-

\frac{269}{225} = 1.19

a = 1.20

8 0
2 years ago
A box sits on a table. A short arrow labeled F subscript N points up. A short arrow labeled F subscript g points down. A long ar
Aloiza [94]

Answer:

unbalanced and right

Explanation:

7 0
2 years ago
Explain what parallel medium boundaries do to the path of the wave after it travels through both boundaries. (air and water)
Brilliant_brown [7]

Answer:

The boundaries cause the waves to change direction an effect called <u>refraction.</u>

Explanation:

When a wave crosses a boundary between different materials, the speed of the wave and its wavelength changes.When passing from air to water the two properties (speed and wavelength) decreases, and the wave is observed to change direction as it crosses the boundary between the two material.The bending of the wave is called refraction.

7 0
3 years ago
A grindstone of radius 4.0 m is initially spinning with an angular speed of 8.0 rad/s. The angular speed is then increased to 12
PSYCHO15rus [73]

Answer: 6.36

Explanation:

Given

Radius of grindstone, r = 4 m

Initial angular speed of grindstone, w(i) = 8 rad/s

Final angular speed of the grindstone, w(f) = 12 rad/s

Time used, t = 4 s

Angular acceleration of the grinder,

α = Δw / t

α = w(f) - w(i) / t

α = (12 - 8) / 4

α = 4/4 = 1 rad/s²

Number of complete revolution in 4s =

Δθ = w(i).t + 1/2.α.t²

Δθ = 8 * 4 + 1/2 * 1 * 4²

Δθ = 32 + 1/2 * 16

Δθ = 32 + 8

Δθ = 40 rad/s

40 rad/s = 40/2π rpm = 6.36 rpm

Therefore, the grindstone does 6.36 revolutions during the 4 s interval

6 0
3 years ago
Calcular la energía cinética de un cometa cuya masa es de 5×10 elevado a 31 kg y se mueve con velocidad de 216000km/h
PolarNik [594]

The kinetic energy is 9\cdot 10^{40}J.

Explanation:

The kinetic energy of an object is given by

K=\frac{1}{2}mv^2

where

K is the kinetic energy of the object

m is the mass of the object

v is the speed of the object

For the comet in this problem, we have:

m=5\cdot 10^{31} kg is its mass

v=216,000 km/h is the speed

First, we convert the speed  from km/h to m/s:

v=216,000 \frac{km}{h} \cdot \frac{1000 m/km}{3600 s/h}=60,000 m/s

Therefore, the kinetic energy of the comet is

K=\frac{1}{2}(5\cdot 10^{31})(60,000)^2=9\cdot 10^{40}J

Learn more about kinetic energy here:

brainly.com/question/6536722

#LearnwithBrainly

5 0
3 years ago
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