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vitfil [10]
3 years ago
13

Determine if the following lengths could represent a triangle. If they can, determine if the triangle, is acute, obtuse, or righ

t.
A. 5, 8, 13
B. 7, 12, 26
C. 11, 15, 20
Mathematics
1 answer:
stiks02 [169]3 years ago
3 0

9514 1404 393

Answer:

  A. no

  B. no

  C. obtuse

Step-by-step explanation:

For side lengths to form a triangle, the sum of the shorter two must exceed the longest.

A. 5 + 8 = 13 . . . . a line segment, not a triangle

B. 7 + 12 < 26 . . . . no closure, not a triangle

C. 11 + 15 > 20 . . . . a triangle. A picture shows it to be obtuse

  You can also compare 11² +15² vs 20² ⇒ 346 vs 400. The long side is too long for a right triangle, so the triangle must be obtuse. (The Pythagorean theorem tells you a right triangle with those legs would have a long side of √346 = 18.6.)

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Kevin counts 75 chicks in the hen house. He also sees more chicks outside the hen house. How can Kevin count to find how many ch
stellarik [79]

What we know:

we know that there are <u>75</u> chicks in the hen house, we also know that in all there are 108 chicks

What we need to find:

we need to find out how many chicks were outside

Answer equation:

108 - 75 = 33

8 0
3 years ago
-17=x-15<br> I'm stuck so can someone help
Strike441 [17]

Answer:

-2

Step-by-step explanation:

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8 0
3 years ago
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Solve for the missing length and the other two angles in the triangle below
Klio2033 [76]

Answer:

AC = 3.72 units

Angles:

A = 132.6°

C = 27.4°

Step-by-step explanation:

AC² = 5² + 8² - 2(5)(8)cos(20)

AC² = 13.82459034

AC = 3.718143399

3.718143399/sin20 = 8/sinA

sinA = 0.7358944647

A = 180 - 47.38285134

A = 132.6171487

3.718143399/sin20 = 5/sinC

sinC = 0.4599340405

C = 27.38285134

5 0
3 years ago
James has 14{,}500\text { g}14,500 g14, comma, 500, start a text, space, g, end text of sand in his sandbox. He brings home anot
mariarad [96]

Question:

James has 14,500g of sand in his sandbox. He brings home another 7,400g of sand from the beach to add to his sandbox. How many kilograms of sand does James have in his sandbox now?

Answer:

The quantity of sandbox James has is 21.9kg

Step-by-step explanation:

Given

Initial quantity of sandbox = 14,500 g

Additional quantity = 7,400 g

Required

Total quantity of sandbox in kg

Tp get the total quantity of sandbox, we simply add in the initial and additional quantity of sandbox together;

This is represented mathematically as follows;

Total = Initial Quantity + Additional Quantity

Total = 14,500 g + 7,400 g

Total = 21,900 g

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1000 g is equivalent to 1 kg

21,900 g will be equivalent to \frac{21,900}{1,000} kg

21,900g = \frac{21,900}{1,000} kg

21,900g = 21.9 kg

Hence, the quantity of sandbox James has is 21.9kg

7 0
3 years ago
A) scrieti toate numerele naturale impare mai mici decat 17
AURORKA [14]

1, 3, 5, 7, 8, 11, 13, 15  is the answer.

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