The chemical reaction involved in this titration process would be:
NaOH(aq) + KHC8H4O4(aq) = KNaC8H4O4(aq) + H2<span>O(l)
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To determine the concentration of the NaOH solution, we, first, need to calculate the moles of NaOH that is used up in the reaction given the amount of KHP solution that is used. We do as follows:
Moles NaOH = 0.500 M KHP ( .025 L solution ) ( 1 mol NaOH / 1 mol KHP ) = 0.0125 mol NaOH reacted
Volume of NaOH solution used = 53.5 mL - 25.0 = 28.5 mL
Molarity is the number of moles of a solute per liter of solution. We calculate as follows:
Molarity of NaOH = 0.0125 mol / .0285 mL = 0.44 M
A: resistor is the answer
Wind abrades rock by sandblasting, this is the process in which wind causes the
Answer:
ΔTb = 0.66 C
Explanation:
Given
Mass of KBr = 185 g
Mass of water = 1.2 kg
Kb = 0.51 C/m
Explanation:
The change in boiling point (ΔTb) is given by the product of molality (m) of the solution and the boiling point constant (Kb)
[tex]\Delta T_{b}= 0.51 C/m * 1.296 m = 0.66 C[\tex]
The electron dot structure for each molecule are:
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a. H:O:O:H
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The partial negative charges are on the Oxygen atoms.
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b. H:Cl:
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The partial negative charge is on the Chlorine atom.
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c. H:Br:
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The partial negative sign is on Bromine atom.
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d. H:O:H
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The partial negative sign is on the Oxygen atom.
