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telo118 [61]
3 years ago
11

HURRY WILL MARK BRAINILEST

Chemistry
2 answers:
Mnenie [13.5K]3 years ago
6 0

Answer:

A

Give Brainliest Please!

natita [175]3 years ago
5 0

Answer:

Explanation:

diffusion has already occurred

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Griffin made the following list of the different outer coverings of a plant. which part of his list is incorrect?
liraira [26]

Stamen is not an outer covering its the reproductive organ of the plants.

<h3>What is use of covering of Plants ?</h3>

Outer covering of plants is useful in protecting them from environment factors , it is useful in keeping the moisture intact inside the plants.

Among the different outer covering , Bark ,stamen , spines and fuzzy hairs

Bark , stamen and fuzzy hairs are all the outer covering of plants

Stamen is not an outer covering its the reproductive organ of the plants.

To know more about outer covering of Plants

brainly.com/question/20411910

#SPJ1

5 0
2 years ago
What name is given to substances in which atoms of two or more elements are chemically combined?
anygoal [31]

Answer:

Compounds

Explanation:

Substances in which atoms of two or more elements are chemically combined are called compounds.

A compound is a substance formed when two or more elements are chemically joined.

5 0
3 years ago
Read 2 more answers
What are interactions between flip flops and sulfuric acid
frosja888 [35]
When the flip flops are used to walk on the ground the sulfuric acid from the ground overtime tends to wear down the bottom of the flip flops
3 0
3 years ago
55.2 mL of 0.500 M potassium hydroxide is used to neutralize 27.4 mL of sulfuric
mr Goodwill [35]

Answer:

0.504 M

Explanation:

Step 1: Write the balanced neutralization reaction

2 KOH + H₂SO₄ ⇒ K₂SO₄ + 2 H₂O

Step 2: Calculate the reacting moles of KOH

55.2 mL (0.0552 L) of 0.500 M KOH react. The reacting moles of KOH are:

0.0552 L × 0.500 mol/L = 0.0276 mol

Step 3: Calculate the moles of H₂SO₄ that reacted with 0.0276 moles of KOH

The molar ratio of KOH to H₂SO₄ is 2:1. The reacting moles of H₂SO₄ are 1/2 × 0.0276 mol = 0.0138 mol

Step 4: Calculate the concentration of H₂SO₄

0.0138 moles of H₂SO₄ are in 27.4 mL (0.0274 L). The molarity of H₂SO₄ is:

[H₂SO₄] = 0.0138 mol/0.0274 L = 0.504 M

6 0
3 years ago
Answer this FAST PLEASE IT WILL HELP ALOT AND THEIR IS 15 POINTS AND ILL GIVE BRAINLIEST!!
amm1812

Answer:

C

Explanation:

As fertilizer can run off into the reservoir and contaminate it with harmful chemicals

8 0
3 years ago
Read 2 more answers
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