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guajiro [1.7K]
2 years ago
11

g A high-energy photon turns into and electron and a positron. (A positron has exactly the same mass as the electron, but opposi

te charge.) What is the longest wavelength that the photon can have for this process to occur
Physics
1 answer:
yawa3891 [41]2 years ago
5 0

Answer:

2 m = E / c^2      where m is mass of electron

E = h v     where v is the frequency ( nu) of the incident photon

E = h c / y      where y is the incident wavelength (lambda)

2 m = h / (c y)

y = h / (2 m c)      wavelength required

y = 6.62 * 10E-34 / (2 * 9.1 * 10E-31 * 3 * 10E8)  m

y = 3.31 / 27.3 E-11 m

y = 1.21 E -12 m   = .0121 Angstrom units

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A uniform magnetic field passes through a horizontal circular wire loop at an angle 19.5 ∘ from the vertical. The magnitude of t
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To solve this problem, we will apply the concepts related to Faraday's law that describes the behavior of the emf induced in the loop. Remember that this can be expressed as the product between the number of loops and the variation of the magnetic flux per unit of time. At the same time the magnetic flux through a loop of cross sectional area is,

\Phi = BA Cos \theta

Here,

\theta = Angle between areal vector and magnetic field direction.

According to Faraday's law, induced emf in the loop is,

\epsilon= -N \frac{d\Phi }{dt}

\epsilon = -N \frac{(BAcos\theta)}{dt}

\epsilon = -NAcos\theta \frac{dB}{dt}

\epsilon = -N\pi r^2 cos\theta \frac{d}{dt} ( ( 3.75 T ) + ( 3.05T/s ) t + ( -6.95 T/s^2 ) t^2)

\epsilon = -N\pi r^2 cos\theta( (3.05T/s)-(13.9T/s)t )

At time t = 5.71s,  Induced emf is,

\epsilon = -(1) \pi (0.220m)^2 cos(19.5\°)(  (3.05T/s)-(13.9T/s)(5.71s))

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3 years ago
Read 2 more answers
Take a look at a bicycle with gears. Using what you have just learned, answer the following questions:
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2 years ago
220V is applied to two different conductors made of the same material. One conductor is twice as long and twice as thick as the
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Answer:

Explanation:

For calculating resistance of a conductor , the formula is

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Given , l₁ = 2l₂ , A₁ = 4A₂ , area is proportional to square of thickness.

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