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Rus_ich [418]
3 years ago
11

How is. X^2=36 rational?

Mathematics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

{x}^{2}  = 36 \\ x =  \sqrt{36 } \\ x = 6 \\ it \: is \: rational \: number \: because \: we \: can \: write \: 6as \: 6 \1 \: it \: is \: in \: the \: form \: of \: p  \q \: where \:  \: q \: i \: not \: equals \: to \: 0

hope this will help you.

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Which of the following statements are correct? Select all that apply.
Marizza181 [45]
For a 7 sides polygon which is called heptagon or septagon
Interior angles = (7-2)*180/7 = 128.57°
Exterior angle = 180 - 128.57 = 51.43°
Central angle = 360/7 = 51.43°

The statements which are correct:

<span>3. The regular polygon ABCDEFG can be broken down into 2 isosceles trapezoids and 1 isosceles triangle
</span>
<span>5. The central angle of the polygon ABCDEFG is about 51.43° and each interior angle is about 128.57°
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<span>7. The central angle ABCDEFG is the same measure of the exterior angle </span>
7 0
3 years ago
Read 2 more answers
Peyton has collected 120 aluminum cans for recycling. If 20 cans will fit in each blue plastic bag, how many bags will she need
gogolik [260]

Hi Renee!

--------------------------------------------

We Know:

120 aluminum cans.

20 cans fit in each blue bag.

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Solution:

120 / 20 = 6

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Answer:

She will need 6 bags to carry all the aluminum cans.

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Hope This Helps :)

6 0
3 years ago
A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Let f(t) be the number of vinyl records s
KIM [24]
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
 PLEASE SEE ATTACHED IMAGE.

 First, we define the variables:
 x: number of years after 1950
 f (x): amount of vinyl sold.
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5 0
3 years ago
Xp+yp=z solve for the variable p
anastassius [24]
Use the distributive property backwards.
xp+yp=z become p(x+y)=x, which solves to p=x/(x+y)
3 0
3 years ago
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