A light wave travels through water (n = 1.33) at an angle of 35°. What angle
2 answers:
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The change in the height of the object is 5.1 m.
<h3>Conservation of mechanical energy</h3>The principle of conservation of mechanical energy states that the total energy of an isolated system is always conserved.
The change in the height of the object is calculated by applying the principle of conservation of mechanical energy as follows;
P.E = K.E
Thus, the change in the height of the object is 5.1 m.
Learn more about conservation of mechanical energy here: brainly.com/question/6852965
Answer:
the terminal velocity v_t= 202.96 m/s≅203 m/s
Explanation:
The expression for the terminal velocity
here, C_d is the drag coefficient for the cylinder is 1.15
The surface density of the air at 20°C is
ρ_surface = 1.2041 kg/m^3
the density of air at an altitude of 39000 m
ρ= 4.3/100×39000 = 0.05177 kg/m^3
now substitute these values in equation above
we get
v_t= 202.96 m/s≅203 m/s
the terminal velocity v_t= 202.96 m/s≅203 m/s