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torisob [31]
3 years ago
10

At a distance of one centimeter from an electron, the electric field strength has a value

Physics
1 answer:
Burka [1]3 years ago
6 0
We are asked in the problem to determine the <span>distance of an electron in which the electric field strength is equal to e/3. we use the gravitational formula of E = m1m2/d^2
hence, 

e = m1m2/1 = k/1 =k
e/2 = k/d^2
e/2=e/d^2
d^2 = 2
d = sqrt 2 = </span><span>1.41 cm</span>
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Answer:

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3 years ago
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What is the ratio of the intensities of an earthquake P wave passing through the Earth and detected at two points 14 km and 49 k
Molodets [167]

Answer:

\dfrac{I_1}{I_2}=12.25

Explanation:

r_1 = 14 km

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So,

\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{I_1}{I_2}=\dfrac{49^2}{14^2}\\\Rightarrow \dfrac{I_1}{I_2}=12.25

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3 years ago
As in the video, we apply a charge +Q to the half-shell that carries the electroscope. This time, we also apply a charge –Q to t
Andreyy89

Answer:

Explanation:

When the positively charged half shell is brought in contact with the electroscope, its needle deflects due to charge present on the shell.

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2 years ago
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Answer:

\omega_f = 585.37 \ rev/s

Explanation:

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