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kirill [66]
3 years ago
5

For the Balanced Reaction: 3 Mg + Fe2O3 → 3 MgO + 2 Fe

Chemistry
1 answer:
trasher [3.6K]3 years ago
7 0

Answer:

3 mol MgO : 2 mol Fe

Explanation:

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Rxn
givi [52]

Answer: The enthalpy of formation of SO_3 is  -396 kJ/mol

Explanation:

Calculating the enthalpy of formation of SO_3

The chemical equation for the combustion of propane follows:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(O_2(g))})]

We are given:

\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-297kJ/mol\\\Delta H^o_{rxn}=-198kJ

Putting values in above equation, we get:

-198=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta -297)+(1\times (0))]\\\\\Delta H^o_f_{(SO_3(g))}=-396kJ/mol

The enthalpy of formation of SO_3 is -396 kJ/mol

4 0
3 years ago
While burning coal and charcoal, you notice that coal releases more heat than charcoal. That means that the... 1. elastic energy
Dafna11 [192]

Answer:

3). Chemical potential energy

1). lower in charcoal than in coal.

Explanation:

Chemical potential energy is defined as the energy that can be absorbed or stored in a substance's chemical bonds. It can be released when there is a change in the number of particles of the substance.

As per the question, coal releases more heat than charcoal because 'the chemical potential energy of charcoal is lower than the coal' <u><em>and hence, the latter would release more heat on burning i.e. the energy that was absorbed in the chemical bonds of the substance</em></u>. Hence, option 3 and 1 are the correct answers.

4 0
3 years ago
C3H8 + 5O2 → 3CO2+ 4H2O, if 5.75L of oxygen are consumed in the above reaction, how many L of carbon dioxide are produced?
anzhelika [568]

Answer: 3.45 L carbon dioxide are produced

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}=\frac{5.75L}{22.4L}=0.257moles

C_3H_8+5O_2(g)\rightarrow 3CO_2+4H_2O  

According to stoichiometry :

5 moles of O_2 produce =  3 moles of CO_2

Thus 0.257 moles of O_2 will produce=\frac{3}{5}\times 0.257=0.154moles  of CO_2  

Volume of CO_2=moles\times {\text {Molar volume}}=0.154moles\times 22.4L/mol=3.45

Thus 3.45 L carbon dioxide are produced

6 0
3 years ago
The temperature of a 500. ml sample of gas increases from 150. k to 350. k. what is the final volume of the sample of gas, if th
maw [93]
<span>pv=nrt; Pressure and moles are constant. p=nr(150k)/.5 L; Pressure initially After temp change pv=nrt; What is volume? v=nr(350k)/p; p is constant so we can substitute from above v=nr(350k)/(nr(150k)/.5 L)) v=350/150/.5 L v=4.66 liters</span>
3 0
3 years ago
Read 2 more answers
a propane torch is lit inside a hot air balloon during preflight preparations to inflate the balloon. which condition of the gas
earnstyle [38]

Answer:

The pressure remains constant

Explanation:

this is an example in charles law where as the temperature increases so does the volume.

5 0
3 years ago
Read 2 more answers
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