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3 years ago

How many grams of sodium phosphate are formed by the reaction of 10 g of sodium with phosphoric acid?

Chemistry

1 answer:

Norma-Jean [14]3 years ago

8 0

Answer:

23.8g of sodium phosphate are formed

Explanation:

Based on the reaction of sodium, Na, with phosphoric acid, H₃PO₄:

3Na + H₃PO₄ → Na₃PO₄ + 3/2 H₂

3 moles of sodium produce 1 mole of sodium phosphate

To solve this question we must find the moles of sodium in 10g. Using the chemical reaction we can find the moles -And the mass- of sodium phosphate produced, as follows:

Moles Na -Molar mass: 22.99g/mol-

10g * (1mol / 22.99g) = 0.435 moles Na

Moles Na₃PO₄:

0.435 moles Na * (1mol Na₃PO₄ / 3mol Na) = 0.145 moles Na₃PO₄

Mass Na₃PO₄ -Molar mass: 163.94g/mol-

0.145 moles Na₃PO₄ * (163.94g/mol) =

<h3>23.8g of sodium phosphate are formed</h3>

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3 years ago

Read 2 more answers

ammonium phosphate is an important ingredient in many solid fertilizers. It can be made by reacting aqueous phosphoric acid with

Kaylis [27]

Answer:

0.57 moles (NH4)3PO4 (2 sig. figs.)

Explanation:

To quote, J.R.

"Note: liquid ammonia (NH3) is actually aqueous ammonium hydroxide (NH4OH) because NH3 + H2O -> NH4OH.

H3PO4(aq) + 3NH4OH(aq) ==> (NH4)3PO4 + 3H2O

Assuming that H3PO4 is not limiting, i.e. it is present in excess

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