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Alina [70]
3 years ago
9

A man attempts to pick up his suitcase of weight ws by pulling straight up on the handle.(Figure 1) However, he is unable to lif

t the suitcase from the floor. Which statement about the magnitude of the normal force n acting on the suitcase is true during the time that the man pulls upward on the suitcase?
A. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase.B. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase minus the magnitude of the force of the pull.C. The magnitude of the normal force is equal to the sum of the magnitude of the force of the pull and the magnitude of the suitcase's weight.D. The magnitude of the normal force is greater than the magnitude of the weight of the suitcase

Physics
2 answers:
Stolb23 [73]3 years ago
8 0

Answer:

The magnitude of the normal force is equal to the magnitude of the weight of the suitcase minus the magnitude of the force of the pull.

Explanation:

aleksandr82 [10.1K]3 years ago
4 0

Answer:B

Explanation:

Given

man is unable to lift the suitcase thus

Magnitude of Normal reaction will  weight minus magnitude of force pull

From FBD

N+F=W_s

N=W_s-F

Where F=Pull Force

N=Normal reaction

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James and John dive from an overhang into the lake below. James simply drops straight down from the edge. John takes a running s
liraira [26]

Answer:

Both of them reach the lake at the same time.

Explanation:

We have equation of motion s = ut + 0.5at²

Vertical motion of James : -

          Initial velocity, u = 0 m/s

         Acceleration, a = g

         Displacement, s = h

    Substituting,

                  s = ut + 0.5 at²

                 h = 0 x t + 0.5 x g x t²

                 t_{James}=\sqrt{\frac{2h}{g}}

Vertical motion of John : -

          Initial velocity, u = 0 m/s

         Acceleration, a = g

         Displacement, s = h

    Substituting,

                  s = ut + 0.5 at²

                 h = 0 x t + 0.5 x g x t²

                 t_{John}=\sqrt{\frac{2h}{g}}

So both times are same.

Both of them reach the lake at the same time.

3 0
3 years ago
What are the three ways of answering a scientific question
My name is Ann [436]

Answer:

Let's start by understanding what exactly a scientific question is. A scientific question is a question that may lead to a hypothesis and help us in answering (or figuring out) the reason for some observation. A good scientific question has certain characteristics. It should have some answers (real answers), should be testable.

Here's examples of a few:

Why is that a star?

or

What is that star made of?

Hope this can lead you to the answer you're looking for at least!!

5 0
3 years ago
CAN SOMEONE PLEASE HELP ME
s2008m [1.1K]
The answer should be B
5 0
3 years ago
while looking at a graph, you notice a period of time where the line is perfectly horizontal what is most likely taking place du
aev [14]

Answer:

where the y axis is

Explanation:

In more simple terms, a horizontal line on any chart is where the y-axis values are equal. If it has been drawn to show a series of highs in the data, a data point moving above the horizontal line would indicate a rise in the y-axis value over recent values in the data sample.

7 0
2 years ago
An object is dropped from rest from a height of 4.1 107 m above the surface of the Earth. If there is no air resistance, what is
Valentin [98]

Answer:

2.83 x 10^4m/s

Explanation:

First, let us calculate the time taken by the object to hit the surface of the earth.

H = 4.1 x 10^7m

g = 9.8m/s2

t = √(2H/g)

t = √((2x 4.1 x 10^7) /9.8)

t = 2892.64secs

Now, we can find the velocity with which the object strikes the earth as follows:

V = gt

V = 9.8 x 2892.64

V = 2.83 x 10^4m/s

3 0
3 years ago
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