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Alina [70]
3 years ago
9

A man attempts to pick up his suitcase of weight ws by pulling straight up on the handle.(Figure 1) However, he is unable to lif

t the suitcase from the floor. Which statement about the magnitude of the normal force n acting on the suitcase is true during the time that the man pulls upward on the suitcase?
A. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase.B. The magnitude of the normal force is equal to the magnitude of the weight of the suitcase minus the magnitude of the force of the pull.C. The magnitude of the normal force is equal to the sum of the magnitude of the force of the pull and the magnitude of the suitcase's weight.D. The magnitude of the normal force is greater than the magnitude of the weight of the suitcase

Physics
2 answers:
Stolb23 [73]3 years ago
8 0

Answer:

The magnitude of the normal force is equal to the magnitude of the weight of the suitcase minus the magnitude of the force of the pull.

Explanation:

aleksandr82 [10.1K]3 years ago
4 0

Answer:B

Explanation:

Given

man is unable to lift the suitcase thus

Magnitude of Normal reaction will  weight minus magnitude of force pull

From FBD

N+F=W_s

N=W_s-F

Where F=Pull Force

N=Normal reaction

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An action force is 40 N to the right. The reaction force must be: A. 20 N left B. 40 N left C. 20 N right D. 40 N right
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if an object is being acted on by two forces a push and a pull of 6N what is the net force of the object
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A solid weighs 200N in air, 150N in water and 170N in a liquid. Find relative density of solid, relative density of liquid and d
fomenos

Answer:

\rho_{s} = 4

\rho_{l} = 0.6

\rho{liq} = 600 kg/m^{3}

Given:

Weight of solid in air, w_{sa} = 200 N

Weight of solid in water, w_{sw} = 150 N

Weight of solid in liquid, w_{sl} = 170 N

Solution:

Calculation of:

1. Relative density of solid, \rho_{s}

\rho_{s} = \frac{w_{sa}}{w_{sa} - w_{sw}}

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2. Relative density of liquid, \rho_{l}

\rho_{l} = \frac{w_{sa} - w_{sl}}{w_{sa} - w_{sw}}

\rho_{l} = \frac{200 - 170}{200 - 150} = 0.6

3. Density of liquid in S.I units:

Also, we know:

\rho{l} = \frac{\rho_{liq}}{\rho_{w}}

where

= {\rho_{liq}} = density of liquid

= {\rho_{w}} = 1000 kg/m^{3} = density of water

Now, from the above formula:

0.6 = \frac{\rho_{liq}}{1000}

\rho{liq} = 600 kg/m^{3}

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