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3 years ago

What elements/isotopes are formed via Big Bang Nucleosynthesis?

Physics

1 answer:

Natali [406]3 years ago

8 0

Answer:

deuterium, helium and lithium

Explanation:

Big Bang nucleosynthesis is defined as the production of nuclei other than Hydrogen during the early phases of the universe but shortly after the occurrence of the Big Bang.

Now, the other nuclei formed are usually the elements deuterium, helium and lithium or their corresponding isotopes.

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A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.

juin [17]

Answer:

Explanation:

Given

For first case

launch angle $\theta =45^{\circ}C$

at highest point $h=150 m/s$

$150=u\cos 45$

$u=\frac{150}{\cos 45}=212.132 m/s$

For second case

$\theta _2=37^{\circ}C$

at highest Point velocity is $u\cos \theta _2$

$=212.132\times \cos 37$

$=169.41 m/s$

as there is no acceleration in x direction therefore horizontal velocity is same

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3 years ago

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Which of the following is true about acids?

Stells [14]

i would say, are sour and corrode metals

8 0

3 years ago

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Why does metal feel cold

ikadub [295]

Answer:

Metal is cold because it is a good conductor. A conductor carries heat away from and object. Heat flows from your hand into the metal and then is conducted rapidly away into the bulk of the metal, leaving the metal surface and your skin surface relatively cool.

Explanation:

You are welcome.

7 0

2 years ago

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Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of

Anna [14]

Given data:

* The extension of the steel wire is 0.3 mm.

* The length of the wire is 4 m.

* The area of cross section of wire is,

$A=2\times10^{-6}m^2$

* The young modulus of the steel is,

$Y=2.1\times10^{11}\text{ Pa}$

Solution:

The young modulus of the steel in terms of the force and extension is,

$Y=\frac{F\times l}{A\times dl}$

where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,

Substituting the known values,

$\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}$

Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.

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1 year ago

Can you answer this please i’ve been stuck on it for a while

sp2606 [1]

The kinetic energy depends on several things like how cute I am

7 0

3 years ago