Hmm that's a tuff one let me think
Answer:
d = 229.5 m
Explanation:
It is given that,
Total mass of a ski-plane is 1200 kg
It lands towards the west on a frozen lake at 30.0 m/s.
The coefficient of kinetic friction between the skis and the ice is 0.200.
We need to find the distance covered by the plane before coming to rest. In this case,

It is decelerating, a = -1.96 m/s²
Now using the third equation of motion to find the distance covered by the plane such that :

So, the plane slide a distance of 229.5 m.
<span> Let,
initial velocity = v m/sec,
Angle, x = 40 degrees,
horizontal-componant = v.cos(x) = 12 m/sec,
OR,
v = 12 / cos(40) = 12/0.766 = 15.67 meters/sec >================< ANSWER </span> Source(s): Fazaldin A <span> · 4 years ago </span>
Answer:
4.15 x 10^6 N
Explanation:
Area, A = 1.43 cm^2 = 1.43 x 10^-4 m^2
mass, m = 60.5 kg
Weight, F = m g = 60.5 x 9.8 = 592.9 N
Pressure = Force / Area
P = Weight / Area
P = 592.9 / (1.43 x 10^-4)
P = 4.15 x 10^6 N
<h3>Answer:</h3><h3>
B ) Nuclear family</h3>
Explanation:
The answer is B because Nuclear family mean a family with two kids and Mrs. Parker have two kids