I think you're talking about Ribosomes?
This is the organelle responsible for protein synthesis.
Answer:
pH = 12.15
Explanation:
To determine the pH of the HCl and KOH mixture, we need to know that the reaction is a neutralization type.
HCl + KOH → H₂O + KCl
We need to determine the moles of each compound
M = mmol / V (mL) → 30 mL . 0.10 M = 3 mmoles of HCl
M = mmol / V (mL) → 40 mL . 0.10 M = 4 mmoles of KOH
The base is in excess, so the HCl will completely react and we would produce the same mmoles of KCl
HCl + KOH → H₂O + KCl
3 m 4 m -
1 m 3 m
As the KCl is a neutral salt, it does not have any effect on the pH, so the pH will be affected, by the strong base.
1 mmol of KOH has 1 mmol of OH⁻, so the [OH⁻] will be 1 mmol / Tot volume
[OH⁻] 1 mmol / 70 mL = 0.014285 M
- log [OH⁻] = 1.85 → pH = 14 - pOH → 14 - 1.85 = 12.15
Answer:
<u>2.26 </u>
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Explanation:
First you should know what are significant figures,
1 . All non - zero digits are significant.
2 . The zero between two non- zero are significant.Ex 302 has 3 significant figures.
3. The zero before the decimal and before any non-zero digit is non significant. Example : 0.003 has only 1 significant figure.
4. The zero after non zero are non - significant . But the zeros after the decimal point are significant.
300 has only 1 significant figure
300.0 has 4 significant figure
The least number of significant figures present in the number should be there in the final answer of the calculation.
Look at the number having minimum significant digits :
It is 3 (every number has 3- significant figures ) So the answer should also contain 3 - significant figures.
First solve the numerator part
Round off this number to 3 significant figures.
Answer is =<u> 2.26</u>
It has 3 - significant digit since all the digits are non-zero.
The empirical formula of benzene is CH
Answer:
6) λ = 0.84 × 10⁻⁸ m
7) λ = 0.84 × 10⁻⁶ m
Explanation:
6) Given data:
Wavelength of photon = ?
Frequency of photon = 3.56 × 10¹⁶ Hz
Solution:
Formula:
Speed of radiation = frequency × wavelength
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 3.56 × 10¹⁶ Hz × λ
λ = 3×10⁸ m/s / 3.56 × 10¹⁶ s⁻¹
λ = 0.84 × 10⁻⁸ m
7) Given data:
Wavelength of photon = ?
Frequency of photon = 6.15 × 10¹⁴ Hz
Solution:
Formula:
Speed of radiation = frequency × wavelength
c = speed of wave = 3×10⁸ m/s
by putting values,
3×10⁸ m/s = 6.15 × 10¹⁴ Hz × λ
λ = 3×10⁸ m/s / 6.15 × 10¹⁴ Hz s⁻¹
λ = 0.84 × 10⁻⁶ m
