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Sever21 [200]
3 years ago
5

****PLEASE HELP**** WILL MARK BRAINLIEST

Physics
1 answer:
allochka39001 [22]3 years ago
4 0

Answer:

The Current decreases

Explanation:

HOPE THIS HELPS!

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Can you explain how to solve each pleade
Kryger [21]

Answer:

Explanation:

The resistance column is correct.

I1 = I2 = I3 = I4 = 2 Amps

So all the currents are the same.

R = 110

I = 2 amps

V = ?

Vt = I * R

Vt = 2 * 110

Vt = 220

=============

V1 = 20 * 2 = 40 volts. That's 40 volts dropped from the right side of R1 to the left side.

V2 = 60 * 2 = 120 volts across the 60 ohm resistor

V3 = 30 * 2 = 60

Total voltage = 40 + 120 + 60

Total voltage = 220 which is just what it should be.

==========================

Power

P1 = V1 * I

P1 = 40 * 2

P1 = 80 watts

P2 = 120*2

P2 = 240

P3 = 60 * 2

P3 = 120

Total Power = 80 + 240 + 120

Total Power = 440

7 0
3 years ago
A diagnostic sonogram produces a picture of internal organs by passing ultrasound through the tissue. In one application, it is
miss Akunina [59]

Answer:

1) \lambda = 11\times 10^{-4} m

2)2.51\times 10^9 Pa

Explanation:

Given data:

speed of sound v  = 1540 m/s

frequency f  = 1.40 MHz = 1.40 \times 10^6 Hz

density \rho = 1060 kg/m^3

1) we know that

v = f\lambda

\lambda = \frac[v}{f} = \frac{1540}{1.40\times 10^6}

\lambda = 11\times 10^{-4} m

2) we know that

v= \sqrt{\frac{modulus}{density}}

v^2 = \frac{\gamma}{\rho}

\gamma = v^2 \rho

\gamma = 1540^2 \times 1060 = 2.51 \times 10^9 Pa

6 0
4 years ago
. Suppose the mass of a fully loaded module in which astronauts take off from the Moon is 1.00 × 104 kg. The thrust of its engin
Viktor [21]

Answer:

a) The module's acceleration in a vertical takeoff from the Moon will be 1.377 \frac{m}{s^2}

b) Then we can say that a thrust of 3*10^{4} N won't be able to lift off the module from the Earth because it's smaller than the module's weight (9.8 *10^{4} N).

Explanation:

a) During a vertical takeoff, the sum of the forces in the vertical axis will be equal to mass times the module's acceleration. In this this case, the thrust of the module's engines and the total module's weight are the only vertical forces. (In the Moon, the module's weight will be equal to its mass times the Moon's gravity acceleration)

T-(m*g)=m*a

Where:

T= thrust =3 *10^{4} N

m= module's mass =1 *10^{4} N

g= moon's gravity acceleration =1.623 \frac{m}{s^2}

a= module's acceleration during takeoff

Then, we can find the acceleration like this:

a=\frac{T}{m} -g=\frac{3*{10}^4 N}{1*{10}^4 kg}-1.623\frac{m}{s^2}

a=1.377 \frac{m}{s^2}

The module's acceleration in a vertical takeoff from the Moon will be 1.377 \frac{m}{s^2}

b) To takeoff, the module's engines must generate a thrust bigger than the module's weight, which will be its mass times the Earth's gravity acceleration.

weight=m*g=(1*{10}^4 kg)*(9.8 \frac{m}{s^2})=9.8 *10^{4} N

Then we can say that a thrust of 3*10^{4} N won't be able to lift off the module from the Earth because it's smaller than the module's weight (9.8 *10^{4} N).

8 0
4 years ago
1. If you have a Periodic Table that is NOT color coded, describe WHERE to look on the Periodic Table to find elements which hav
igor_vitrenko [27]
The periodic table is arranged in a way that trends are present in columns and rows. Elements belonging to the same column belongs to the same family which means they have the same properties. Elements belonging to the same row have the same number of electron shells. Example of elements with the same chemical properties are Na, Li, and K all belonging to the same group.
3 0
4 years ago
Match the adaptations with their benefits.Match the adaptations with their benefits.
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Wasp stinger protection from predators. Peacocks bright plumage to help obtain mate. Owls large eyes to help search for food. Bears fur to help maintain homeostasis
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3 years ago
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