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pickupchik [31]
3 years ago
7

Name the device of measurement and write its used or its function?​

Physics
1 answer:
labwork [276]3 years ago
4 0

Answer:

There is a lot of instruments used for measurement, may I ask which one are you referring to?

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Which of these phase changes requires energy?
frutty [35]

Answer:

A

Explanation:

You have to give energy away for B. You have to think about that carefully. The CO2 starts out with a great deal of energy (mostly KE) and has to slow down to go from gas to a solid. Not B

In general C is the same way. Water has more energy than ice. Not C

Same principle in D.  Not D.

So it's A

7 0
2 years ago
Sand falls from an overhead bin and accumulates in a conical pile with a radius that is always threethree times its height. Supp
hammer [34]

Answer:

159241.048 cm³/s

Explanation:

r = Radius = 3×height = 3h

h = height = 16 cm

Height of the pile increases at a rate = \frac{dh}{dt}=22\ cm/s

\text{Volume of cone}=\frac{1}{3}\pi r^2h\\\Rightarrow V=\frac{1}{3}\pi (3h)^2h\\\Rightarrow V=3\pi h^3

Differentiating with respect to time

\frac{dv}{dt}=9\pi h^2\frac{dh}{dt}\\\Rightarrow \frac{dv}{dt}=9\pi 16^2\times 22\\\Rightarrow \frac{dv}{dt}=159241.048\ cm^3/s

∴ Rate is the sand leaving the bin at that​ instant is 159241.048 cm³/s

5 0
3 years ago
Knowing the constant g what will the gravitational force between two masses be if the gravitational force between them is 36n an
charle [14.2K]
The gravitational force between two masses is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the two masses
r is the separation between the two masses

We see that the force is proportional to the inverse of the square of the distance: F \sim  \frac{1}{r^2}
therefore, if the distance is tripled:
r'=3r
The force decreases by a factor 1/9:
F \sim  \frac{1}{(3r)^2}= \frac{1}{9}  \frac{1}{r^2}

Since the original force was 36 N, the new force will be
F' =  \frac{1}{9} (36 N)= 4 N
6 0
3 years ago
A man of mass 85 kg runs up a flight of stairs of height 4.6 m in a time period
seraphim [82]

Explanation:

a) Power = work / time = force × distance / time

P = Fd/t

P = (85 kg × 9.8 m/s²) (4.6 m) / (12 s)

P ≈ 319 W

b) P = Fd/t

0.70 (319 W) = (m × 9.8 m/s²) (4.6 m) / (9.6 s)

m = 47.6 kg

7 0
3 years ago
Q. A mass of 300g is lifted to a<br> height of 10m<br> 205 by a person. Calculate his work done
sergiy2304 [10]
A=mgh
m=300g=0.3kg
g=9,81 m/s^2
h=10m
A=29.43J
3 0
2 years ago
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