Doesn't seem like we know much here, but we can answer it. Let's talk about what we know. We know it takes 3.24 s for the ball to go up and drop back down again. We know that gravity is the only force acting after the ball leaves the hand, so a = 9.8 m/s^2 (we'll say it's negative in our equations because down being negative is intuitive). We also know that it stops moving for a brief moment at the top of the arc, where v = 0 m/s. Because gravity is the only force, and it slows it down on the way up at the same rate it speeds it up on the way down and the distance covered in upward and downward motion is the same, we can confidently say that it will reach the top of its arc (where v = 0 and it turns around) in half the total time it is in the air, so it takes 1.62 s to reach the peak. Now we can use a kinematics equation, let's use vf = vi + a*t, where vf is final velocity and is 0, vi is initial velocity and is some unknown v we need to solve for, a is acceleration and is -9.8 m/s^2 and t is time and since this is just to the top of the arc, we'll use half the time so 1.62 s. We can solve for vi and plug stuff in like so: v = -a*t = -(-9.8m/s^2)*(1.62s) = 15.876 m/s.
Answer:
Yes
Explanation:
Tube worms are living creatures.
Answer:
Avogadro's law.
Explanation:
Avogadro’s law states that, equal volumes of all gases at the same temperature and pressure contain the same number of molecules.
Mathematically,
V n
V = Kn where V = volume in cm3, dm3, ml or L; n = number of moles of gas;
K = mathematical constant.
The ideal gas equation is a combination of Boyle's law, Charles' law and Avogadro’s law.
V 1/P at constant temperature (Boyle’s law)
V T at constant pressure ( Charles’law)
V n at constant temperature and pressure ( Avogadro’s law )
Combining the equations yields,
V nT/P
Introducing a constant,
V = nRT/P
PV = nRT
Where P = pressure in atm, Pa, torr, mmHg or Nm-2; V = volume in cm3, dm3, ml or L; T = temperature in Kelvin; n = number of moles of gas in mol; R = molar gas constant = 0.082 dm3atmK-1mol-1
Answer:
Δt ≈ 2.9137 ≈ 3 seconds per kilometer
Explanation:
The speed of light is approximately 300000 km /s, while the speed fo the sound in the air is 0.3432 km/s.
The light takes therefore this time to travel one kilometer
On the other hand the sound takes this time to travel one kilometer
t = 2.9137 s
Then the delay time is 2.9137 -
Δt ≈ 2.9137 ≈ 3 s
Disk of dust and gas contains the new born stars and as well as young stars and the Halo region contains the old stars.
The different regions of a spiral galaxy like our Milky way tend to have characteristic populations of stars.
Halo: The halo tends to have older, red stars. In general, blue stars are larger but since they are also hotter, tend to run through their fuel faster and have shorter lives. Halo stars tend to be older stars, The halo is generally lacking in dust and low in metals.
Bulge: The outer Area of the bulge has mostly older red stars. The inner bulge has active star formation and has a mix of red and blue stars.
Disk: The disk has active star formation regions, so there are young blue stars in that region. Here are the stars that are both old stars and young stars. The blue stars are largely found on the edges of the spiral arms.
Thus disk with the dust clouds contains new and young stars. And halo region contains old stars.
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