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Natali5045456 [20]
3 years ago
9

The emission spectrum of iodine is shown below. Which is the absorption spectrum?

Physics
1 answer:
garik1379 [7]3 years ago
6 0
Sorry Sorry Sorry Sorry Sorry Sorry Sorry Sorry
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A stalled car is pushed with a force of 342N from rest. How far does the car travel in 12 seconds if it’s mass is 989kg
allsm [11]

24.89m

Explanation:

Given parameters:

Force on car = 342N

Initial velocity = 0

Time taken = 12s

Mass of the car = 989kg

Unknown:

Distance covered by the car = ?

Solution:

To solve this problem, we simply use one of the appropriates equations of motions.

                     s = ut + \frac{1}{2}at²

   s is the distance

    u is the initial velocity

    t is the time taken

    a is the acceleration of the car.

To find the acceleration;

       Acceleration = \frac{Force }{mass} = \frac{342}{989}

          Acceleration = 0.35m/s²

Inputting the parameters in the equation:

           s = 0 x 12 + \frac{1}{2} x 0.35 x 12² = 24.89m

Learn more:

Velocity brainly.com/question/10962624

#learnwithBrainly

6 0
3 years ago
What are input energy and output energy?​
makkiz [27]

Answer:

Explanation:

Input​ refers to the amount of energy put into a device, and ​ output​ refers to the amount of energy that comes out. A device may change the type of energy but not the amount. For example, a light bulb's input energy is the form of electrical energy, and its output energy is in the form of light and heat. Efficiency.

3 0
3 years ago
Development occurs:
Alex73 [517]

Answer:

D

Explanation:

:(

4 0
3 years ago
Match the situation with the energy type.
anastassius [24]

Answer:

snowplow would be m, sun r , hb n , FB e ,and tiaa c

8 0
3 years ago
A person jumps off a diving board 5.0 m above the water's surface into a deep pool. The person's downward motion stops 2.2 m bel
shutvik [7]

Answer:

9.9 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 5+0^2}\\\Rightarrow v=9.9\ m/s

If the body has started from rest then the initial velocity is 0. In order to find the velocity just before hitting the water then the distance at which the downward motion stops is irrelevant.

Hence, the speed of the diver just before striking the water is 9.9 m/s

7 0
3 years ago
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