The amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.
<h3>
Total capacitance of the circuit</h3>
The total capacitance of the circuit is calculated as follows;
Capacitors in series;
1/Ct = 1/8 + 1/7.5
1/Ct = 0.25833
Ct = 3.87 mF
Capacitors is parallel;
Ct = 3.87 mF + 12 mF + 15 mF
Ct = 30.87 mF
Ct = 0.03087 F
<h3>Charge in each capacitor</h3>
Q = CV
Q = 0.03087 x 12
Q = 0.37 C
Thus, the amount of electric charge that resides on each capacitor once it is fully charged is 0.37 C.
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the total electric potential at location P, which is at the center of the rectangle is 0V.
The charges placed at the corner of the rectangle are same in magnitude but different in charge. hence the total electric potential will be same in magnitude but different in charge and will be cancelled. Similarly, all the total electric potential will be cancelled and resultant will be zero.
<h3>
What is total electric potential?</h3>
- The amount of labor required to convey a unit of electric charge from a reference point to a given place in an electric field is known as the electric potential (also known as the electric field potential, potential drop, or the electrostatic potential).
- More specifically, it is the energy per unit charge for a test charge that is negligibly disruptive to the field under discussion. In order to prevent the test charge from gaining kinetic energy or radiating, the travel across the field is also meant to occur with very little acceleration.
- The electric potential at the reference location is, by definition, zero units. Any point may be used as the reference point, but typically it is earth or a point at infinity.
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Answer:
The velocity of the blades is 88.185 m/s.
Explanation:
Given;
length of the blade, r = 80 m
angular speed, ω = 1 rev per 5.7 seconds
The velocity of the blades is calculated by applying the following circular motion equation that relates linear velocity (V) and angular speed (ω);
Therefore, the velocity of the blades is 88.185 m/s.
