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maria [59]
2 years ago
10

Two carts are free to slide along the frictionless track shown in figure below. Cart A of mass m1 = 8 kg is released from 12m. A

cart B of mass m2 = 4 kg, initially at rest. The two carts combine together and move as one object. Calculate the height reached
by the two carts after collision.
Physics
1 answer:
Harrizon [31]2 years ago
3 0

The height reached by the two carts after collision is determined as 5.34 m.

<h3>Initial velocity of Cart A</h3>

Apply the principle of conservation of mechanical energy.

K.E = P.E

v = √2gh

v = √(2 x 9.8 x 12)

v = 15.34 m/s

<h3>Final velocity of the two carts after the collision</h3>

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

8(15.34) + 4(0) = v(8 + 4)

122.72 = 12v

v = 10.23 m/s

<h3>Height reached by both carts</h3>

Apply the principle of conservation of mechanical energy.

P.E = K.E

mgh = ¹/₂mv²

h = v²/(2g)

h = (10.23²) / (2 x 9.8)

h = 5.34 m

Learn more about linear momentum here: brainly.com/question/7538238

#SPJ1

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Serjik [45]

Answer :

1) Luster →  the shininess of a material

2) Freezing point → temperature at which a liquid becomes a solid

3) Viscosity → the measure of a substance's resistance to flow

4) Solubility → ability to dissolve in another substance

5) Ductility → able to be pulled into a wire

Explanation :

Luster : It is defined as the material which has the shining property.

Freezing point : It is the temperature at which the phase changes from liquid state to solid state at low temperature.

Viscosity : It measures the resistance of the liquids to flow .

Solubility : It is defined as the ability of a substance (solute) to dissolve into a liquid (solvent).

Ductility : It is defined as the ability of a metal into a thin wire without breaking.

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4 years ago
A car goes from 80 kn/h to 20 km/h in 0.5 h. What is the acceleration in km/h^2? *
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Answer:

<h2>In physics, acceleration is defined as the rate of change of the velocity of an object with respect to time. That is A = VF - VI /T; </h2><h2></h2><h2>Where A =  Acceleration </h2><h2>VF = Final velocity = 20 km </h2><h2>VI = Initial velocity = 80 km </h2><h2>T= Time = 0.5 hr </h2><h2>A = (20 - 80)/ 0.5 = - 60/.5  </h2><h2>A = - 120 Km/ hr^2 </h2><h2></h2><h2>Therefore, the acceleration of the car is -120 km/hr^2. </h2><h2> Because the value is negative, the appropriate name that describe it is deceleration.</h2><h2>I Hope this helps</h2>

3 0
3 years ago
a 15 kg tv sots on a shelf at a height of 0.3 m. how much gravitational potential energy is added to the television when it is l
nata0808 [166]
Gravitational potential energy can be described as m*g*h (mass times gravity times height).

Originally,
15kg * 9.8m/s^2 *0.3 m = 44.1 kg*m^2/s^2 = 44.1 Joules.

After it is moved to a 1m shelf:
15kg * 9.8m/s * 1 = 147 kg*m^2/s^2= 147 Joules.

To find how much energy was added, we subtract final energy from initial energy:

147 J - 44.1 J = 102.9 Joules.
6 0
3 years ago
Two particles of equal masses (m = 5.5x10-15 kg) are released from rest with a distance between them is equal to 1 m. If particl
Tcecarenko [31]

To solve this problem it is necessary to resort to the energy conservation equations, both kinetic and electrical.

By Coulomb's law, electrical energy is defined as

EE = \frac{kq_1q_2}{d}

Where,

EE = Electrostatic potential energy

q= charge

d = distance between the charged particles

k = Coulomb's law constant

While kinetic energy is defined as

KE = \frac{1}{2} mv^2

Where,

m= mass

v = velocity

There by conservation of energy we have that

EE= KE

There is not Initial kinetic energy, then

\frac{kq_1q_2}{d}-\frac{kq_1q_2}{d'} = 2*\frac{1}{2}mv_f^2

\frac{kq_1q_2}{d}-\frac{kq_1q_2}{d'} = mv_f^2

v_f^2= \frac{\frac{kq_1q_2}{d}-\frac{kq_1q_2}{d'} }{m}

v_f = \sqrt{\frac{\frac{kq_1q_2}{d}-\frac{kq_1q_2}{d'}}{m}}

Replacing with our values we have,

v_f = \sqrt{\frac{\frac{(9*10^9)(12*10^{-6})(60*10^{-6})}{1}-\frac{(9*10^9)(12*10^{-6})(60*10^{-6})}{3}}{5.50*10^{-15}}}

v_f = 2.802*10^7m/s

Therefore the speed of particle B at the instat when the particles are 3m apart is 2.802*10^7m/s

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4 years ago
Which of the following statements is false?
soldi70 [24.7K]

Answer:

c

Explanation:

it is impossible to have negative acceleration

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