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2 years ago

Method used to separate ethanol from propanol

1 answer:

N76 [4]2 years ago

8 0

Fractional distillation is a method for separating a liquid from a mixture of two or more liquids. For example, liquid ethanol can be separated from a mixture of ethanol and water by fractional distillation. This method works because the liquids in the mixture have different boiling points.

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The gas-phase reaction follows an elementary rate law and is to be carried out first in a PFR and then in a separate experiment

astraxan [27]

Answer:

The activation energy is $=8.1\,kcal\,mol^{-1}$

Explanation:

The gas phase reaction is as follows.

$A \rightarrow B+C$

The rate law of the reaction is as follows.

$-r_{A}=kC_{A}$

The reaction is carried out first in the plug flow reactor with feed as pure reactant.

From the given,

Volume "V" = $10dm^{3}$

Temperature "T" = 300 K

Volumetric flow rate of the reaction $v_{o}=5dm^{3}s$

Conversion of the reaction "X" = 0.8

The rate constant of the reaction can be calculate by the following formua.

$V= \frac{v_{0}}{k}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]$

Rearrange the formula is as follows.

$k= \frac{v_{0}}{V}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]............(1)$

The feed has Pure A, mole fraction of A in feed $y_{A_{o}}$ is 1.

$\epsilon =y_{A_{o}}\delta$

$\delta$ = change in total number of moles per mole of A reacte.

$=1(2-1)=1$

Substitute the all given values in equation (1)

$k=\frac{5m^{3}/s}{10dm^{3}}[(1+1)ln \frac{1}{1-0.8}-1 \times 0.8] = 1.2s^{-1}$

Therefore, the rate constant in case of the plug flow reacor at 300K is $1.2s^{-1}$

The rate constant in case of the CSTR can be calculated by using the formula.

$\frac{V}{v_{0}}= \frac{X(1+\epsilon X)}{k(1-X)}.............(2)$

The feed has 50% A and 50% inerts.

Hence, the mole fraction of A in feed $y_{A_{o}}$ is 0.5

$\epsilon =y_{A_{o}}\delta$

$\delta$ = change in total number of moles per mole of A reacted.

$=0.5(2-1)=0.5$

Substitute the all values in formula (2)

$\frac{10dm^{3}}{5dm^{3}}=\frac{0.8(1+0.5(0.8))}{k(1-0.8)}=2.8s^{-1}$

Therefore, the rate constant in case of CSTR comes out to be $2.8s^{-1}$

The activation energy of the reaction can be calculated by using formula

$k(T_{2})=k(T_{1})exp[\frac{E}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})]$

In the above reaction rate constant at the two different temperatures.

Rearrange the above formula is as follows.

$E= R \times(\frac{T_{1}T_{2}}{T_{1}-T_{2}})ln\frac{k(T_{2})}{k(T_{1})}$

Substitute the all values.

$=1.987cal/molK(\frac{300K \times320K}{320K \times300K})ln \frac{2.8}{1.2}=8.081 \times10^{3}cal\,mol^{-1}$

$=8.1\,kcal\,mol^{-1}$

Therefore, the activation energy is $=8.1\,kcal\,mol^{-1}$

8 0

3 years ago

You take out your best silver spoons and notice that they are very dull and have some black spots, chemical or physical change?

lions [1.4K]

Answer:

chemical

Explanation:

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3 years ago

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What do food webs begin with as the first source of energy A plants B consumers C the sun D decomposers

atroni [7]

Answer:

C:sun

Explanation:

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3 years ago

2NaOH + H2SO4 --> Na2SO4 + 2H2O

iren2701 [21]

Answer:

Sodium hydroxide, a base, reacts with sulfuric acid to form sodium sulfate (complete neutralization) and water. If you write the balanced equation, you will see that 2 moles of sodium hydroxide react with 1 mole of sulfuric acid to form 1 mole of sodium sulfate and 2 moles of water. Therefore it would take .25 moles of sulfuric acid to react with .5 moles of sodium hydroxide.

Explanation:

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2 years ago

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Which three of the following statements accurately describe the blood buffering system in humans? The blood buffering system...

ikadub [295]

Answer:

b) maintains the pH of blood near 7.4.

c) regulates the blood pH at 7.4 +/- one pH unit.

f) is facilitated by the enzyme carbonic anhydrase, which interconverts carbon dioxide and water to carbonic acid (ionizes into bicarbonate and H^+).

Explanation:

The pH of human blood is slightly acidic i. e. 7.4. The enzyme carbonic anhydrase is responsible for the regulation to neutral and prevent it from acidic. the enzyme carbonic anhydrase helps in the conversion of carbon dioxide to carbonic acid and bicarbonate ions. When the blood reach to lungs, the bicarbonate ions convert back to CO2 and this carbondioxide is exhaled from the body.

4 0

3 years ago

Method used to separate ethanol from propanol​

Method used to separate ethanol from propanol