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gayaneshka [121]

3 years ago

10

The equation below is for potassium oxide.

2 answers:

Reika [66]3 years ago

7 0

The answer is C 4:1.

Sonja [21]3 years ago

4 0

Answer:

c

Explanation:

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A moving object has a kinetic energy of 20 J. if it’s velocity doubles, it’s kinetic energy would be

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A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I

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The acceleration is $a = 3.45*10^{3} m/s^2$

Explanation:

From the question we are told that

The radius is $d = 6.5 cm = \frac{6.5}{100} = 0.065 m$

The magnitude of the magnetic field is $B = 5.5 T$

The rate at which it decreases is $\frac{dB}{dt} = 24.5G/s = 24.5*10^{-4} T/s$

The distance from the center of field is $r = 1.5 cm = \frac{1.5}{100} = 0.015m$

According to Faraday's law

$\epsilon = - \frac{d \o}{dt}$

and $\epsilon = \int\limits {E} \, dl$

Where the magnetic flux $\o = B* A$

E is the electric field

dl is a unit length

So

$\int\limits {E} \, dl = - \frac{d}{dt} (B*A)$

${E} l = - \frac{d}{dt} (B*A)$

Now $l$ is the circumference of the circular loop formed by the magnetic field and it mathematically represented as $l = 2\pi r$

A is the area of the circular loop formed by the magnetic field and it mathematically represented as $A= \pi r^2$

So

${E} (2 \pi r)= - \pi r^2 \frac{dB}{dt}$

$E = \frac{r}{2} [ - \frac{db}{dt} ]$

Substituting values

$E = \frac{0.015}{2} (24*10^{-4})$

$E = 3.6*10^{-5} V/m$

The negative signify the negative which is counterclockwise

The force acting on the proton is mathematically represented as

$F_p = ma$

Also $F_p = q E$

So

$ma = qE$

Where m is the mass of the the proton which has a value of $m = 1.67 *10^{-27} kg$

$q = 1.602 *10^{-19} C$

So

$a =\frac{1.60 *10^{-19} *(3.6 *10^{-5}) }{1.67 *10^{-27}}$

$a = 3.45*10^{3} m/s^2$

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