Data:
Arsenic Molar Mass = 74,9216 ≈ 75 u (<span>atomic mass unit)</span>
Solving:
1 mole of arsenic → 75g ------------ 6,02*10²³ molecules
..................................X -------------- 1 molecule
6,02*10²³X = 75
Dominant allele
Explanation:
An allele whose trait shows up in an organism when the allele is present is called a dominant allele.
An allele whose trait does not show up in an organism when present is called a recessive allele.
- An allele is the two possible forms of gene.
- A gene can be dominant or recessive in nature.
- An allele is a DNA that occupies a particular locus on a chromosome.
- They usually occur in pairs.
- The allele determines hereditary characteristics.
Learn more:
Genetics brainly.com/question/10607948
#learnwithBrainly
Answer:
a) The equilibrium will shift in the right direction.
b) The new equilibrium concentrations after reestablishment of the equilibrium :
![[SbCl_5]=(0.370-x) M=(0.370-0.0233) M=0.3467 M](https://tex.z-dn.net/?f=%5BSbCl_5%5D%3D%280.370-x%29%20M%3D%280.370-0.0233%29%20M%3D0.3467%20M)
![[SbCl_3]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M](https://tex.z-dn.net/?f=%5BSbCl_3%5D%3D%286.98%5Ctimes%2010%5E%7B-2%7D%2Bx%29%20M%3D%286.98%5Ctimes%2010%5E%7B-2%7D%2B0.0233%29%20M%3D0.0931%20M)
![[Cl_2]=(6.98\times 10^{-2}+x) M=(6.98\times 10^{-2}+0.0233) M=0.0931 M](https://tex.z-dn.net/?f=%5BCl_2%5D%3D%286.98%5Ctimes%2010%5E%7B-2%7D%2Bx%29%20M%3D%286.98%5Ctimes%2010%5E%7B-2%7D%2B0.0233%29%20M%3D0.0931%20M)
Explanation:
a) Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
On increase in amount of reactant
If the reactant is increased, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where more product formation is taking place. As the number of moles of 
is increasing .So, the equilibrium will shift in the right direction.
b)
Concentration of = 0.195 M
Concentration of 
= 
Concentration of 
=
On adding more 
to 0.370 M at equilibrium :
Initially
0.370 M 
At equilibrium:
(0.370-x)M 
The equilibrium constant of the reaction = 
The equilibrium expression is given as:
![K_c=\frac{[SbCl_3][Cl_2]}{[SbCl_5]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BSbCl_3%5D%5BCl_2%5D%7D%7B%5BSbCl_5%5D%7D)
On solving for x:
x = 0.0233 M
The new equilibrium concentrations after reestablishment of the equilibrium :
Answer:
The mantel. I'm pretty sure.
Explanation:
Answer:
H3PO4 Mol mass..
= (3 x H1 = 3) + (1 x P31 = 31) + (4 x O16 = 64). = 98g/mol.
a)..Hydrogen: = 3 / 98 = 0.0306 x 100% = 3.06%.
b)..Phosphorus = 31/98 = 0.3162 x 100% = 31.63%.
c)..Oxygen = 64/98 = 0.6531 x 100% = 65.31%.
(Total = 100% H3PO4).
Explanation:
Find the molar mass of all the elements in the compound in grams per mole.
Find the molecular mass of the entire compound.
Divide the component's molar mass by the entire molecular mass.
You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.
