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3 years ago

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How many atoms are present in 3 moles of chromium?

2 answers:

Lena [83]3 years ago

5 0

1 mole chromium -------------- 6.02 x 10²³ atoms
3 moles chromium ------------ ( atoms chromium )

atoms chromium = 3 x ( 6.02 x 10²³) / 1

atoms chromium = 1.806 x 10²⁴ / 1

= <span>1.806 x 10²⁴ atoms of chromium

hope this helps!</span>

DENIUS [597]3 years ago

4 0

In any element or substance, one mole of the substance is equivalent to 6.022 x10^23 atoms per mole. This is expressed as the Avogadro's number which is useful in finding out the total number of atoms in a sample. In this case, we are given with 3 moles of chromium. this is equivalent to 1.8066 x1024 atoms

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If you mixed three Dixie cups’ contents together containing 0.05L of 1.0M lemonade, 0.05L of 2.5M lemonade, and 0.05L of 0.5M le

viva [34]

Molarity of the resulting solution will be 1.33 M.

<u>Explanation:</u>

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For cup 2 = 2.5 M × 0.05 L= 0.125 moles

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3 0

3 years ago

Please help me with this question!!

mestny [16]

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$ $\text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles$

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According to stoichiometry :

1 mole of $Cl_2$ produce = 2 moles of $NaCl$

Thus 7.04 moles of $Cl_2$ will produce= $\frac{2}{1}\times 7.04=14.08moles$ of $NaCl$

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Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

3 0

3 years ago

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lions [1.4K]

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<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=icRT$

where,

$\pi$ = osmotic pressure of the solution = 24 atm

i = Van't hoff factor = 2 (for NaCl)

c = concentration of solute = ?

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T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

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Hence, the concentration of solute is 0.503 mol/L

5 0

3 years ago