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2 years ago

PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer these correctly!!!! (40pts)

Physics

2 answers:

Grace [21]2 years ago

7 0

Answer:

Bernoulli is A

Archimedes is B

Pascal is C

Explanation:

Hope this helps dude

likoan [24]2 years ago

5 0

Answer:

Pascal's Law = C

Archimedes's Law = B

Bernoulli's Law = A

Explanation:

Alrighty, here are the prinicples needed:

In Pascal's law, he states that the pressure applied to an enclosed fluid is directly transmitted without the change in magnitidue. With that, magnitude in every point of the fluid and the walls of the container are remained unchanged. To say simply,the fluid is equal to the pressure at any point in all directions.

$P=\frac{F}{A}$

Where:

F = Force

A = Area

Archimedes Law states that the buoyant force is the weight of the fluid displaced. When any boat displaces a weight of water equal to its own weight, it floats. This is often called the “principle of flotation” where a floating object displaces a weight of fluid equal to its own weight.

$F_{b} = -pgV$

Fb = buoyant force

-p = fluid density

g = acceleration due to gravity

V = fluid volume

The Bernoulli law states that total energy per unit mass of flowing fluid, at any point in the subsurface, is the sum of the kinetic, potential, and fluid-pressure energies and is equal to a constant value.

I hope that this provided you with some clarification and that you have a nice day. I would be happy to help you again in the future. :D

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"Without forces there can be no movement"- Do you agree with this statement? Why or Why not?

myrzilka [38]

Answer: Yes.

Explanation: It is clearly stated in Newton’s first law of physics that an object will not change its motion unless a force acts on.

6 0

3 years ago

A mass of 0.5 kg hangs motionless from a vertical spring whose length is 1.10 m and whose unstretched length is 0.50 m. Next the

ser-zykov [4K]

Answer:

The maximum length during the motion is $L_{max} = 1.45m$

Explanation:

From the question we are told that

The mass is $m =0.5 kg$

The vertical spring length is $L = 1.10m$

The unstretched length is $L_{un} = 1.30m$

The initial speed is $v_i = 1.3m/s$

The new length of the spring $L_{new} = 1.30 m$

The spring constant k is mathematically represented as

$k = -\frac{F}{y}$

Where F is the force applied $= m * g = 0.5 * 9.8=4.9N$

y is the difference in weight which is $=1.10-0.50=0.6m$

The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)

Now substituting values accordingly

$k = \frac{4.9}{0.6}$

$= 8.17 N/m$

The elastic potential energy is given as $E_{PE} = \frac{1}{2} k D^2$

where D is this the is the displacement

Since Energy is conserved the total elastic potential energy would be

$E_T = initial \ elastic\ potential \ energy + kinetic \ energy$

$E_T = \frac{1}{2} k D_{max}^2 = \frac{1}{2} k D^2 + \frac{1}{2} mv^2$

Substituting value accordingly

$\frac{1}{2} *8.17 *D_{max}^2 =\frac{1}{2} * 8.17*(1.30 - 0.50)^2 + \frac{1}{2} * 0.5 *1.30^2$

$4.085 * D_{max}^2 = 3.69$

$D^2_{max} = 0.9033$

$D_{max} = 0.950m$

So to obtain total length we would add the unstretched length

So we have

$L_{max} = 0.950 + 0.5 = 1.45m$

5 0

2 years ago

Read 2 more answers

Ana kicks a stationary 0.2kg soccer ball. The ball leaves her foot at a speed of 20 m/s.

elena55 [62]

Answer:a. 24 kg m/s

b. 3/5s

Explanation:

a.impulse is the change in momentum so at first the momentum is zero because the ball was at rest and the final momentum is 1.2kg*20m/s=24 kg m/s

so the impulse would be (24-0) kg m/s=24 kg m/s

b. so the impulse equation is impulse is force *delts time

so 24 kg m/s=40N*t

t=24 kg m/s /40N=3/5 s

6 0

2 years ago

What is the approximate velocity of the object at 5 seconds ? .

Gnoma [55]

Answer:

do you have an image?

Explanation:

3 0

3 years ago

Your friend's 10.8 g graduation tassel hangs on a string from his rearview mirror. When he accelerates from a stoplight, the tas

Nitella [24]

The tension in the string holding the tassel and the vertical will the tension in the string

T = 0.1953 N
Ф = 34.4 °

<h3>What is the tension in the string holding the tassel. ?</h3>

Generally, the equation for Tension is mathematically given as

$TCos\theta = mg$

Therefore

$TCos6.58^{o} = 19.8*10^{-3}*9.8$

T = 0.1953 N

b).

Where

$T* sin \theta = ma$

$0.1953*Sin6.58 \textdegree = 19.8*10^{-3}*a$

a = 1.13 m/s^2

In conclusion

T* sinФ = ma

2msinФ = ma

2sinФ = a

$sin\theta = \frac{a}{2}$

$\theta = sin^{-1}\frac{a}{2} \\\\\theta= sin^{-1}\frac{1.13}{2}$

Ф = 34.4 °

In conclusion, The tension in the string holding the tassel and the vertical will the tension in the string

T = 0.1953 N

Ф = 34.4 °