Question

If I dilute 250 mL of 0.50 M lithium acetate solution to a volume of 750 mL, what will the concentration of this solution be?​

Answer 1

Answer:

The right answer is "0.17 M".

Explanation:

The given values are:

Volume,

V₁ = 250 mL

V₂ = 750 mL

Molarity,

M₁ = 0.50 M

M₂ = ?

As we know,

⇒  $M_1 V_1=M_2 V_2$

or,

⇒  $M_2=\frac{M_1 V_1}{V_2}$

On substituting the values, we get

⇒        $=\frac{0.50\times 250}{750}$

⇒        $=\frac{125}{750}$

⇒        $=0.17 \ M$