The highest concentration of water would be found in the 5% solution. The concentration given above is percent of glucose, so the solution contain 5% of glucose and 95% of water. Comparing it to 10% of glucose solution which will have 10% glucose and 90% water, clearly, it is the 5% solution that has the highest amount of water in the solution. <span>Percentage
by a certain unit is the amount of that unit of a component in a mixture per 100 units of the
total mixture. </span>
2C4H10 + 13O2 = 8CO2 + 10H2O
1. (2.06g C4H10)/(58.12 g/mol C4H10) = 0.035mol C4H10
2. (0.035molC4H10)(10 mol H2O/2mol C4H10) = 0.177mol H2O
3. (0.177mol H2O)(18.01g/mol H2O) = 3.19g H2O
it will go radio microwave infrared ultraviolet
Answer:
The right option is B
Explanation:
The frequency of the wave is given by the following formula:
where,
f = frequency of the wave.
c = speed of the light.
λ = wavelength of the light.
Therefore the correct option is B.
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first determine the equation. KHP is a monoprotic acid, so it reacts with NaOH in a 1:1 ratio.
<span>a) HKC8H4O4 + NaOH → NaKC8H4O4 + H2O </span>
<span>This allows you to calculate the molarity of NaOH, from the equation V1M1n2 = V2M2n1 </span>
<span>Molarity times volume will give you the number of moles of acid. You can work this out by dividing the mass used by the molar mass. For this question, you will have 1.0115/204.2285 moles KHP, so this value can be substituted for V1M1 in the equation. You need 38.46 mL of NaOH to titrate all the acid, so this will be V2. Now you find M2. </span>
<span>b) 1.0115/204.2285 × 1 = 38.46 × M2 × 1, so M2 = 0.0001288M </span>
<span>Now go on to part 3. Here, you use a similar calculation. The acid and base react in a 1:1 ratio, so n1 = n2 = 1. M2 = 0.1905 and V2 = 25.62. V1M1 will be calculated. </span>
<span>V1M1 × 1 = 25.62×0.0001288×1 = 0.003299856 </span>
<span>Now mass divided by molar mass = V1M1, so molar mass = mass/V1M1. </span>
<span>1.2587/0.003299856 = 381.44 g/mol</span>
