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2 years ago

Eaterfication experiment

Chemistry

1 answer:

Schach [20]2 years ago

8 0

Answer:

Do you mean Esterification experiment?

Explanation:

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Answer: a

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Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. K2SO4 NH4I CoCl3

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The substance that releases the greatest amount of ions will have the greatest attractive forces within its solution, resulting in a reduced freezing point.
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2 years ago

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1 year ago

Which activity is an example of poor personal hygiene

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2 years ago

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What is Y? 222/86 Rn A/z + 4/2He

kondaur [170]

$^{222}_{\phantom{2}86}\text{Rn} \to ^{218}_{\phantom{2}84}\text{Po}+ ^{4}_{2}\text{He}$

Y is Po-218.

A = 218
Z = 84.

<h3>Explanation </h3>

$^{222}_{\phantom{2}86}\text{Rn} \to ^{A}_{Z}\text{Y}+ ^{4}_{2}\text{He}$

Here's the symbol of a particle in a nuclear reaction. $^{A}_{Z}\text{Y}$ .

A stands for mass number. Z stands for atomic number. Both numbers shall conserve in a nuclear reaction.

The mass number on the left hand side is 222.
The two mass numbers on the right hand side add up to A + 4.
222 = A + 4.
A = 218

So is the case for the atomic number. Try figure out the atomic number of Y using the same approach.

The atomic number on the left hand side is 86.
The two atomic number on the right hand side add up to __ + __.
86 = __ + __.
Z = 84.

What element is Y? The atomic number of Y is 84. Refer to a periodic table. Element 84 corresponds to Po (polonium). Y is Polonium-218. The symbol of Y should be written as $^{218}_{\phantom{2}84}\text{Po}$ . Hence the equation:

$^{222}_{\phantom{2}86}\text{Rn} \to ^{218}_{\phantom{2}84}\text{Po}+ ^{4}_{2}\text{He}$ .

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2 years ago

Eaterfication experiment ​

Eaterfication experiment