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MAXImum [283]
3 years ago
6

Eaterfication experiment ​

Chemistry
1 answer:
Schach [20]3 years ago
8 0

Answer:

Do you mean Esterification experiment?

Explanation:

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What is the correct answer?
aksik [14]
I think the answer is c
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A person's _____ changes as he travels from the earth to space, but his _____ remains the same.
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A persons weight changes as he travels from earth to space but his mass remains the same
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Cual es la finalidad de las citas en el texto argumentativo<br><br><br><br><br><br><br>​
Genrish500 [490]

Answer:

Dar crédito a la persona u organización cuyas ideas está usando (y evitar acusaciones de plagio). Mostrarle a su audiencia que su argumento es bueno porque consultó a expertos y también pensó en el tema usted mismo.

Explanation:

5 0
3 years ago
The combustion of 1.5011.501 g of fructose, C6H12O6(s)C6H12O6(s) , in a bomb calorimeter with a heat capacity of 5.205.20 kJ/°C
avanturin [10]

Answer : The internal energy change is -2805.8 kJ/mol

Explanation :

First we have to calculate the heat gained by the calorimeter.

q=c\times (T_{final}-T_{initial})

where,

q = heat gained = ?

c = specific heat = 5.20kJ/^oC

T_{final} = final temperature = 27.43^oC

T_{initial} = initial temperature = 22.93^oC

Now put all the given values in the above formula, we get:

q=5.20kJ/^oC\times (27.43-22.93)^oC

q=23.4kJ

Now we have to calculate the enthalpy change during the reaction.

\Delta H=-\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat gained = 23.4 kJ

n = number of moles fructose = \frac{\text{Mass of fructose}}{\text{Molar mass of fructose}}=\frac{1.501g}{180g/mol}=0.00834mole

\Delta H=-\frac{23.4kJ}{0.00834mole}=-2805.8kJ/mole

Therefore, the enthalpy change during the reaction is -2805.8 kJ/mole

Now we have to calculate the internal energy change for the combustion of 1.501 g of fructose.

Formula used :

\Delta H=\Delta U+\Delta n_gRT

or,

\Delta U=\Delta H-\Delta n_gRT

where,

\Delta H = change in enthalpy = -2805.8kJ/mol

\Delta U = change in internal energy = ?

\Delta n_g = change in moles = 0   (from the reaction)

R = gas constant = 8.314 J/mol.K

T = temperature = 27.43^oC=273+27.43=300.43K

Now put all the given values in the above formula, we get:

\Delta U=\Delta H-\Delta n_gRT

\Delta U=(-2805.8kJ/mol)-[0mol\times 8.314J/mol.K\times 300.43K

\Delta U=-2805.8kJ/mol-0

\Delta U=-2805.8kJ/mol

Therefore, the internal energy change is -2805.8 kJ/mol

5 0
3 years ago
If you had continued following the water molecule in the Water Cycle Activity, what step do you predict would have occurred next
tamaranim1 [39]

Answer:option D is the correct answer, precipitation and it is because water is being released from the cloud into the earth.

Explanation:

PRECIPITATION is the process by which water condenses in the atmosphere. Precipitation can occur in form of snow,fog, dew,rain etc.

Atmospheric water is found in clouds and water vapor. Gradually and systematically the entire atmosphere rotates around the planet. When weather is being formed one of the most common results is precipitation.

In the water molecule activity here, precipitation will occur because water is being released from the atmosphere into the earth.

8 0
3 years ago
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