Hi can someone pls help me with this

This is the chemical formula for acetic acid (the chemical that gives the sharp taste to vinegar):

Anastaziya [24]

Answer:

0.017 mol

Explanation:

CH3COOH - acetic acid - we can write as C2O2H4

From formula C2O2H4 we can see that ratio C: O = 2:2 = 1:1, so number of moles C and O are the same.

So if we have 0.017 mol C, we should have 0.017 mol O.

3 0

3 years ago

In the reaction C5H8 + __O2 → 8H2O + 5CO2, what coefficient should be placed in front of O2 to balance the reaction?

Eduardwww [97]

it is actually nine

5 0

4 years ago

Calculate the equilibrium constant for the reaction below given that [Cl2] = 0.37 M, [H2] = 0.27 M, and [HCl] = 0.95 M at equili

cluponka [151]

Answer:

The equilibrium constant is 9.034.

Explanation:

Every reversible chemical reaction, as in this case, occurs in both directions: the reagents are transformed into products (direct reaction) and the products are transformed back into reagents ( reverse reaction).

The general way in which a reversible reaction can be written is:

aA + bB ⇔ cC + dD

where A, B, C and D represent the chemical species involved and a, b, c and d their respective stoichiometric coefficients.

The chemical equilibrium is the state in which the direct and indirect reaction have the same reaction rate, and is expressed by a constant Kc. This constant is defined as:

$Kc=\frac{[A]^{a}*[B]^{b} }{[C]^{c} *[D]^{d} }$

This constant is equal to the multiplication of the concentrations of the products elevated to their stoichiometric coefficients divided the multiplication of the concentrations of the reactants elevated to their stoichiometric coefficients. In Kc only gases and aqueous solutions come into play and only depends on the temperature.

You have the reaction:

Cl₂(g) + H₂(g) ⇌ 2 HCl(g)

So, in this case, the constant Kc is:

$Kc=\frac{[HCl]^{2} }{[Cl_{2} ]*[H_{2}] }$

Then:

$Kc=\frac{(0.95 M)^{2} }{0.37 M*0.27 M}$

Kc= 9.034

The equilibrium constant is 9.034.

7 0

3 years ago

A 645 g piece of iron is plunged into 375 g of water. The temperature of the water increases from 26 C to 87 C. If the heat capa

jeka94

Answer:

417 °C

Explanation:

From the question given above, the following data were obtained:

Mass of iron (Mᵢ) = 645 g

Specific heat capacity of iron (Cᵢ) = 0.449 J/gºC

Mass of water (Mᵥᵥ) = 375 g

Initial temperature of water (Tᵥᵥ) = 26 °C

Equilibrium temperature (Tₑ) = 87 °C

Specific heat capacity of water (Cᵥᵥ) = 4.184 J/gºC

Initial temperature of iron (Tᵢ) =?

The initial temperature of iron can be obtained as follow:

Heat lost by iron = heat gain by water

MᵢCᵢ(Tᵢ – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)

645 × 0.449(Tᵢ – 87) = 375 × 4.184 (87 –26)

289.605(Tᵢ – 87) = 1569 × 61

289.605Tᵢ – 25195.635 = 95709

Collect like terms

289.605Tᵢ = 95709 + 25195.635

289.605Tᵢ = 120904.635

Divide both side by 289.605

Tᵢ = 120904.635 / 289.605

Tᵢ ≈ 417 °C

Thus, the original temperature of the iron is 417 °C

7 0

3 years ago

If you have 10 grams of a substance that decays with a half-life of 14 days, then how much will you have after 70 days?

scoundrel [369]

Answer:

a. 0.31 g

Explanation:

It is known that the decay of a radioactive isotope isotope obeys first order kinetics.

Also, it is clear that in first order decay the half-life time is independent of the initial concentration.

Half-life time is the time needed for the reactants to be in its half concentration.

If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).

The half-life time of the substance = 14 days.

So, 70 days represent (70 days/ 14 days = 5.0 half-lives).

So, the substance will decay:

10 g → (first half-life = 14 days) 5 g → (second half-life = 28 days) 1.5 g → (third half-life = 42 days) 1.25 g → (fourth half-life = 56 days) 0.625 g → (fifth half-life = 70 days) 0.3125 g.

So, the right choice is: a. 0.31 g.

4 0

3 years ago