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julsineya [31]
2 years ago
14

if your total amout of liquid in milliliters is 10 and you total amout of water in milliliters is 7.what is the consentration of

water in liquid? PLS help fast
Chemistry
1 answer:
Dominik [7]2 years ago
7 0

3 concentration of the water

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What is true of a gas
velikii [3]

Answer:

did you have options, cause if you did chose something alond the lines of

Explanation:

A real gas is a gas that does not behave as an ideal gas due to interactions between gas molecules. A real gas is also known as a nonideal gas because the behavior of a real gas in only approximated by the ideal gas law.

3 0
2 years ago
Imagine that you helped to discover a new element; A=302;Z=119. How many protons, electrons, and neutrons are in each atom it th
oee [108]

Explanation:

Given that,

Mass number, A = 302

Atomic number, Z = 119

We know that, atomic number = no of protons

Protons = 119

Mass no. = No. of neutrons + No. of protons

302 = No. of neutrons + 119

No. of neutrons = 302 - 119

= 183

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5 0
2 years ago
The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th
MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

\frac{K_1}{K_2}=?

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol

Answer:

0.4284 is the ratio of the rate constants.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}

\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}

where,

K_2 = rate constant reaction -1

K_1 = rate constant reaction -2

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = 25^oC=273+25=298 K

Now put all the given values in this formula, we get

\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340

0.4284 is the ratio of the rate constants.

7 0
3 years ago
Why do oxygen and hydrogen connect (attach) underwater? ​
Usimov [2.4K]
The slight positive charges on the hydrogen atoms in water molecules attract the slight negative charges on the oxygen atoms of the other water molecules
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A box contains a mixture of small copper spheres and small lead spheres that are the same size. The total volume of both metals
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38% is the answer to the question
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