Answer:
Empirical CHO2
Molecular C2H2O4
Explanation:
To determine the formulas, firstly, we need to divide the percentage compositions by the atomic masses.
Kindly note that the atomic mass of carbon, oxygen and hydrogen are 12, 16 and 1 respectively. We proceed with the division as follows:
C = 26.7/12 = 2.225
H = 2.2/1 = 2.2
O = 71.1/16 = 4.44375
We then proceed to divide by the smallest value which is 2.2 in this case
C = 2.25/2.2 = 1
H = 2.2/2.2 = 1
O = 4.44375/2.2 = 2
Thus, the empirical formula is CHO2
We now proceed to get the molecular formula as follows
[12+ 1 + 16(2) ]n = 90.04
45n = 90.04
n = 90.04/45 = 2
The molecular formula is :
C2H2O4
The value for this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
<h3>What is an aqueous reaction in
equilibrium?</h3>
When a chemical reaction happens at the liquid state and the formation of reactant and product is the same then the reaction is known as an aqueous reaction in equilibrium denoted by K.
δG = − R T ln
R = universal gas constant 8.313
δG= 20. 46 kj/mol
T = 298 k or 24.4 in celcius.
substituting the value in the equation.
20. 46 kj/mol = 8.313 × 24.4 in celcius × K
K = 8.313 × 24.4 in celcius / 20. 46 kj/mo
k = 9.91 mol .
Therefore, The value of this aqueous reaction at 298 k? a b↽−−⇀c dδ°=20. 46 KJ/mol is 9.91 mol. in equilibrium
Learn more about the aqueous reaction in equilibrium, here:
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A. Variables, this is because you can choose what you're testing
Answer
In a diagnostic test for leukemia, a person receives 4.1 ML of a solution containing selenium-75. If the activity of the selenium-75 is 41 ,uCi/ML what dose, in microcuries, does the patient receive?
