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emmainna [20.7K]
3 years ago
10

A substance in a specific state of matter with volume of 6 liters was transferred to a 12 liter container. The substance took up

the
A. It is highly compressible.
B. It also has a definite shape.
C.Its particles slide past one another
D. Its intermolecular forces are of high strength.
Chemistry
2 answers:
azamat3 years ago
4 0

Answer:

a

Explanation:

salantis [7]3 years ago
4 0

\huge\color{yellow}\boxed{Answer:}

My answer is C.Its particles slide past one another

\huge\color{yellow}\boxed{toshiro hitsugaya}

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An idle ball on a hilltop, though not moving, contains _____.
vampirchik [111]

potential energy because it has a potential to roll down the hill, creating kinetic energy. it is idle

6 0
3 years ago
What is the molarity of a solution made from 0.250 mol of sodium hydroxide and 500 mL of water?
Arlecino [84]

Answer:

\boxed {\boxed {\sf 0.5 \ M \ NaOH}}

Explanation:

Molarity is a measure of concentration in moles per liter.

molarity= \frac{moles}{liters}

There are 0.250 moles of sodium hydroxide (NaOH) and 500 milliliters of water. We need to convert milliliters to liters. Remember that 1 liter contains 1000 milliliters.

\frac{1 \ L}{1000 \ mL}

500 \ mL*\frac{1 \ L}{1000 \ mL}

500*\frac{1 \ L}{1000 }

\frac{500}{1000} \ L=0.5 \ L

Now we have the values to solve for molarity:

  • moles= 0.250 mol NaOH
  • liters= 0.5 L

Substitute the values into the formula.

molarity= \frac{0.250 \ mol \ NaOH}{0.5 \ L}

Divide.

molarity= 0.5 \ mol \ NaOH/ L

  • 1 mole per liter (mol/liter) is equal to 1 Molar or M.
  • Our answer of 0.5 moles of sodium hydroxide per liter is equal to 0.5 M NaOH

molarity= 0.5 \ M \ NaOH

The molarity of the solution is <u>0.5 M NaOH</u>

8 0
3 years ago
Is water wet? I honestly really need to know-
Eva8 [605]

Answer:

yesh water is whet.

Explanation:

4 0
3 years ago
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If 75 gm's of codeine phosphate is dissolved in 1.5 liters of sterile water, what is the resultant percentage strength of the so
Slav-nsk [51]

Answer:

w/v% = gm per 100 ml

75gm X gm 7500

------- = ------ == --------

1500ml 100ml 1500X

X=5%

5 0
3 years ago
QUESTION 4
Firdavs [7]
Firstly, next time you post questions, I suggest you split the questions up so the format is easier to read.

Question 4:
If you use Hess's Law. you subtract the enthalpy of formation of the reactants from the enthalpy of formation of the products. Therefore, Question 4 is "The enthalpy of formation reactions."

Question 5:
Reactions that release heat have a negative enthalpy overall. Therefore, Question 5 is:

<span>PCl3(l) + 1/2 O2(g) → POCl3(l) ΔH = -325.7 kJ

PCl3(g) + Cl2(g) → PCl5(g) ΔH = -92.5 kJ

Question 6:
As said in Question 4, you subtract the enthalpies of formation of the reactants. Therefore, Question 6 is </span><span>N2 (g) and H2 (g).

Question 7:
Balancing the equation, we get:

2 NO2 --> O2 + 2NO

Now using Hess's Law to calculate enthalpy:

(0.0 + 2(90.37))-2(33.85)
=113.0 (Rounding using sig figs)

Therefore, Question 7 is 113.0 kJ.

Question 8:

If you are multiplying by one, you aren't changing anything; therefore, Question 8 is "It must be left alone."</span>
6 0
3 years ago
Read 2 more answers
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