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alina1380 [7]
3 years ago
14

When light rays appear to be coming from behind a mirror, what type of image has been formed

Chemistry
2 answers:
rusak2 [61]3 years ago
8 0
The image<span> formed by a plane </span>mirror<span> is always virtual (meaning that the light rays </span>do<span> not actually come from the </span>image<span>), upright, and of the same shape and size as the object it is reflecting. A virtual </span>image<span> is a copy of an object formed at the location from which the light rays </span>appear<span> to come.</span>
luda_lava [24]3 years ago
4 0
I believe the answer is virtual. because a virtual image is a copy of an object formed at the location from which the light rays appear<span> to come from, simply meaning that the answer has to be virtual. :)</span>
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What is the concentration of a solution in which 10.0 g of AgNO3 is dissolved in 500 mL of solution?
Zigmanuir [339]

molar concentration of AgNO₃ solution = 0.118 mole/L

Explanation:

Because we have the volume of the solution and there is no information about the density of the solution I will asume that you ask for the molar concentration.

number of moles = mass / molecular weight

number of moles of AgNO₃ = 10 / 170 = 0.0588

molar concentration = number of moles / volume (L)

molar concentration of AgNO₃ solution = 0.0588 / 0.5

molar concentration of AgNO₃ solution = 0.118 mole/L

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An automobile is driving uphill. Which form of energy is not involved in this process?
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Waters states of matter include steam liquid water and ice. What about water is the same in the states? What can you conclude ab
julia-pushkina [17]
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5 0
3 years ago
Se ha añadido un evaporador para una alimentación de 11500 kg/dia de zumo de pomelo de forma que evapore 3000 kg/dia de agua por
mamaluj [8]

Answer:

37 %.

Explanation:

¡Hola!

En este caso, para el problema descrito, conocemos la corriente de entrada y la de salida del agua, por lo que podemos obtener el flujo de la corriente que contiene el zumo a la salida una vez el agua fue evaporada:

F_{sol}=11500kg/dia-3000kg/dia=8500 kg/dia

Luego, por medio de un balance de zumo de limón en el evaporador en el cual la cantidad que entra es igual a la que sale con sus respectivas concentraciones:

x_z^{entra}*11500kg/dia=x_z^{sale}*8500kg/dia

Como la concentración del zumo a la salida es del 50 % (0.50), la de entrada es:

x_z^{entra}=\frac{x_z^{sale}*8500kg/dia}{11500kg/dia} =\frac{0.50*8500kg/dia}{11500 kg/dia}\\ \\x_z^{entra}=0.37

Que es igual al 37%.

¡Saludos!

6 0
3 years ago
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