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3 years ago

When light rays appear to be coming from behind a mirror, what type of image has been formed

2 answers:

8 0

The image formed by a plane mirror is always virtual (meaning that the light rays do not actually come from the image), upright, and of the same shape and size as the object it is reflecting. A virtual image is a copy of an object formed at the location from which the light rays appear to come.

luda_lava [24]3 years ago

4 0

I believe the answer is virtual. because a virtual image is a copy of an object formed at the location from which the light rays appear to come from, simply meaning that the answer has to be virtual. :)

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Solution A has a pH of 10, and solution B has a pH of 1. Which statement best describes these solutions?

Free_Kalibri [48]

Answer:

Solution A is a Weak Alkali, Solution B is a strong Acid.

Explanation:

At pH 10, the colour is blue, therefore it's a weak alkali.

At pH 1, the colour is red, therefore it's a strong Acid.

7 0

3 years ago

(kco3s+ ∆→kcl s o2g) es exotérmica o endotermica? justifica tu respuesta.

posledela

Answer:

? can u explain. Not sure what ur asking

Explanation:

8 0

3 years ago

Two moles of a monatomic ideal gas are contained at a pressure of 1 atm and a temperature of 300 K; 34,166 J of heat are transfe

anygoal [31]

Answer:

Final temperature is 302 K

Explanation:

You can now initial volume with ideal gas law, thus:

V = $\frac{n.R.T}{P}$

Where:

n are moles: 2 moles

R is gas constant: 0,082 $\frac{atm.L}{mol.K}$

T is temperature: 300 K

P is pressure: 1 atm

V is volume, with these values: 49,2 L

The work in the expansion of the gas, W, is: 1216 J - 34166 J = -32950 J

This work is:

W = P (Vf- Vi)

Where P is constant pressure, 1 atm

And Vf and Vi are final and initial volume in the expansion

-32950 J = -1 atm (Vf-49,2L) × $\frac{101325 J}{1 atm.L}$

Solving: Vf = 49,52 L

Thus, final temperature could be obtained from ideal gas law, again:

T = $\frac{P.V}{n.R}$

Where:

n are moles: 2 moles

R is gas constant: 0,082 $\frac{atm.L}{mol.K}$

P is pressure: 1 atm

V is volume: 49,52 L

T is final temperature: 302 K

I hope it helps!

4 0

3 years ago

67.4 cm= __________ km

Darya [45]

Answer: it would be 0.000674 km

Explanation:

7 0

3 years ago

Why Xe have electronegativity?

Elza [17]

Answer:

Unlike other noble gases, which are highly nonreactive, Kr and Xe have non-zero values of Electronegativity (3.00 and 2.60, respectively) because they do form compounds: indeed, the electronegativity is a fundamental property of atoms that defines how strong their pull on shared electrons is.

5 0

3 years ago