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Alik [6]
3 years ago
6

Is anyone good at chemistry if so can someone help me please ?

Chemistry
1 answer:
saveliy_v [14]3 years ago
4 0

We're given the [OH⁻] as 8.34 × 10⁻¹² M. Using the formula pOH = -log[OH⁻], the pOH of this solution would be -log(8.34 × 10⁻¹²) ≈ 11.08.

The pOH is, for lack of a better term, the "opposite" of pH: A pOH of 7 is neutral; a pOH less than 7 is <em>basic</em>; and a pOH greater than 7 is <em>acidic</em>.

This follows from the relation, pH + pOH = 14. In this case, with a pOH of 11.08, our pH would be 14 - 11.08 = 2.92, which is acidic (pH < 7).

Thus, the correct answer choice is B.

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Liquid crystal molecules have very unique structures, allowing them to be highly affected by electric fields, changing their orientation in the liquid crystal structure. This is why they are used in LCD screens. They are also highly sensitive to changes in temperature. Therefore the answer is C.
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What is the molar solubility in water of ag2cro4 ? (the ksp for ag2cro4 is 8 x 10-12. )
nikitadnepr [17]

The molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

<h3>How do you define Solubility ?</h3>

The measure of the degree to which a substance gets dissolved in a solvent to become a solution.

The formula for determination of molar solubity is

\rm K_{sp} =  [A^+]^a [B^-]^b

\rm K_{sp}          = solubility product constant

\rm [A^+]^a  =     cation in an aqueous solution

\rm  [B^-]^b  = anion in an aqueous solution

a, b          = relative concentrations of a and b

We have the data given as

\rm K_{sp} for Ag₂CrO₄ is 8 x 10⁻¹²

For Silver chromate , the solubility would be only one-half of the Ag⁺ concentration.

We denote the solubility of Ag₂CrO₄ as S mol L⁻¹.

Then for a saturated solution, we have

[Ag⁺]=2S

[CrO₂⁴⁻]=S

the relation between the solubility and the solubility product constant depends on the stoichiometry of the dissolution reaction

(2S)²(S)=4S³ = 8 * 10⁻¹²

S=∛ (2*10⁻¹²)

S= 1.26 * 10⁻⁴ M

2S = 2.52 * 10⁻⁴ M

Therefore the molar solubility in water of Ag₂CrO₄ is 2.52 * 10⁻⁴ M .

To know more about Solubility

brainly.com/question/8591226

#SPJ4

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2 years ago
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