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Gwar [14]
3 years ago
5

Due to the change in the number of electrons, the metal and nonmetal atoms both become _____

Chemistry
2 answers:
mario62 [17]3 years ago
6 0
The answer is ions , i need to have 20 words so yeah dhajzbajs dhakabxbsjsjs
dexar [7]3 years ago
6 0
An ion is a charged atom or molecule. It is charged because the number of electrons do not equal the number of protons in the atom or molecule. ... When an atom is attracted to another atom because it has an unequal number of electrons and protons, the atom is called an ION.
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Calculate the mass, in grams, of cucl2 (mw = 134.452 g/mol) required to prepare 250.0 ml of a 6.11 % w/v cu2 (mw = 63.546 g/mol)
Sever21 [200]

6.11% w/v of Cu2+ implies that 6.11 g of Cu2+ is present in 100 ml of the solution

therefore,  250 ml of the solution would have: 250 ml * 6.11 g/100 ml = 15.275 g

# moles of Cu2+ = 15.275 g/63.546 g mole-1 = 0.2404 moles

1 mole of CuCl2 contain 1 mole of Cu2+ ion

Hence, 0.2404 moles of Cu2+ would correspond to 0.2404 moles of CuCl2

Molar mass of CuCl2 = 134.452 g/mole

The mass of CuCl2 required = 0.2404 moles * 134.452 g/mole = 32.32 grams

6 0
3 years ago
The chemical compound, "AB" has a molar mass of 74.548 g/mol.
sladkih [1.3K]

Answer:

47.55%

Explanation:

4 0
2 years ago
The gold-foil experiment was used to discover which subatomic particle? Question 2 options: electrons protons ==> neutrons (m
Gelneren [198K]
Proton, the gold foil experiment indicated that the nucleus has a positive charge.
8 0
2 years ago
Read 2 more answers
Chemical Reactions
irakobra [83]

Answer:

It works by separating the fuel from the oxygen. The oxygen comes from the air. It is the same oxygen we breathe. Since the oxygen has to be in contact with the fuel, if you can coat the fuel with something that keeps the oxygen away, the fire will go out which is what the fire extinguisher does.

6 0
2 years ago
How many grams of water at 50◦c must be added to 16 grams of ice at −12◦c to result in only liquid water at 0◦c?
melisa1 [442]

When water at 50 C is added to ice at -12 C, heat is transferred from hot water to ice.

- Heat given out by water = Heat absorbed by ice

Calculating the heat released by hot water:

q = m CwaterΔTq = m (4.184\frac{J}{(g.^{0}C)} )(0^{0}C-50^{0}C)

Calculating heat absorbed by 16 g of ice: Ice at -12^{0}C is converted to ice at O^{0}C and then ice at O^{0} C to water at 0^{0}C

q = m CiceΔT + m (Heat of fusion)

q = 16 g(2.11\frac{J}{g.^{0}C})(0^{0}C - (-12^{0}C)) + 16 g (333.55\frac{J}{g})

q = 405.12 J +5336.8 J =5741.92 J

- Heat given out by water = Heat absorbed by ice

-(m(4.184\frac{J}{g.^{0}C})(0^{0}C-50^{0}C) = 5741.92 J

m = 27.4 g

Therefore, 27.4 g water at 50^{0}C must be added to 16 g of ice at -12^{0}C to convert to liquid water at 0^{0}C

4 0
3 years ago
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